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44 questions
Additional Mathematics/Paper 2/Factors of polynomials
CAIEO-Level4037-o · Paper 2

Factors of polynomials

44 questions· page 1 of 5

Q12025 Oct/Nov·P235MMedium-Easy

It is given that p(x)=ax37x2bx+9\mathrm{p}(x) = ax^3 - 7x^2 - bx + 9, where aa and bb are constants.
x3x - 3 is a factor of p(x)\mathrm{p}(x).
When p(x)\mathrm{p}(x) is divided by x+2x + 2 the remainder is 35-35.

Find the values of aa and bb.

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Q32024 Oct/Nov·P222 partsMedium-Easy
(a)

Given that x=2x = 2 and x=1x = -1 are roots of the equation p(x)=0\mathrm{p}(x) = 0, find aa and bb.

(b)

Solve the equation p(x)=0\mathrm{p}(x) = 0.

Q32023 May/Jun·P222 partsEasy
(a)

Show that x+3x + 3 is a factor of 12+23x+3x22x3-12 + 23x + 3x^2 - 2x^3.

(b)

The curve y=5+33x+3x22x3y = -5 + 33x + 3x^2 - 2x^3 and the line y=10x+7y = 10x + 7 intersect at three points, AA, BB and CC. These points are such that the xx-coordinate of AA has the least value and the xx-coordinate of CC has the greatest value. Show that BB is the mid-point of ACAC.

Q42022 May/Jun·P216MMedium

The polynomial p(x)=mx317x2+nx+6\mathrm{p}(x) = mx^3 - 17x^2 + nx + 6 has a factor x3x - 3. It has a remainder of 12-12 when divided by x+1x + 1. Find the remainder when p(x)\mathrm{p}(x) is divided by x2x - 2.

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Q52022 Oct/Nov·P225MMedium

DO NOT USE A CALCULATOR IN THIS QUESTION.

Find the xx-coordinates of the points of intersection of the curves y=7x37x217x4y = 7x^3 - 7x^2 - 17x - 4 and y=x32x24x16y = x^3 - 2x^2 - 4x - 16.

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Q42021 May/Jun·P226MMedium

The polynomial p(x)=mx329x2+39x+n\mathrm{p}(x) = mx^3 - 29x^2 + 39x + n, where mm and nn are constants, has a factor 3x13x - 1, and remainder 6 when divided by x1x - 1. Show that x2x - 2 is a factor of p(x)\mathrm{p}(x).

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Q32020 May/Jun·P213 partsEasy
(a)

Find the remainder when p(x)\mathrm{p}(x) is divided by x+1x + 1.

(b)(i)

Show that x+2x + 2 is a factor of p(x)\mathrm{p}(x).

(b)(ii)

Write p(x)\mathrm{p}(x) as a product of linear factors.

Q42020 May/Jun·P225MMedium

The three roots of p(x)=0\mathrm{p}(x) = 0, where p(x)=2x3+ax2+bx+c\mathrm{p}(x) = 2x^3 + ax^2 + bx + c are x=12x = \frac{1}{2}, x=nx = n and x=nx = -n, where aa, bb, cc and nn are integers. The yy-intercept of the graph of y=p(x)y = \mathrm{p}(x) is 4. Find p(x)\mathrm{p}(x), simplifying your coefficients.

Similar questions
Q32019 May/Jun·P222 partsMedium-Easy
(i)

Given that x2x - 2 is a factor of ax312x2+5x+6ax^3 - 12x^2 + 5x + 6, use the factor theorem to show that a=4a = 4.

(ii)

Showing all your working, factorise 4x312x2+5x+64x^3 - 12x^2 + 5x + 6 and hence solve 4x312x2+5x+6=04x^3 - 12x^2 + 5x + 6 = 0.

Q72019 Oct/Nov·P222 partsMedium-Easy
(a)

The cubic equation x3+ax2+bx40=0x^3 + ax^2 + bx - 40 = 0 has three positive integer roots. Two of the roots are 2 and 4. Find the other root and the value of each of the integers aa and bb.

(b)

Do not use a calculator in this question.

Solve the equation x35x246x40=0x^3 - 5x^2 - 46x - 40 = 0 given that it has three integer roots, only one of which is positive.