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Additional Mathematics/Paper 1/[Legacy] Indices and surds
CAIEO-Level4037-o · Paper 1

[Legacy] Indices and surds

40 questions· page 1 of 4

Q22025 May/Jun·P124MMedium-Easy

Solve the equation x13+1=6x13x^{\frac{1}{3}} + 1 = \frac{6}{x^{\frac{1}{3}}}.

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Q52024 May/Jun·P123 partsMedium
(a)

Find the perimeter of the trapezium, giving your answer in its simplest form.

(b)

Find the area of the trapezium, giving your answer in the form p7+qp\sqrt{7}+q, where pp and qq are rational numbers.

(c)

Find cotDBC\cot \angle DBC, giving your answer in the form r7+sr\sqrt{7}+s, where rr and ss are simplified rational numbers.

Q52023 May/Jun·P112 partsMedium
(a)

You are given that cos120°=12\cos 120° = -\frac{1}{2}, sin120°=32\sin 120° = \frac{\sqrt{3}}{2} and tan120°=3\tan 120° = -\sqrt{3}.

In the triangle ABCABC, AB=536AB = 5\sqrt{3} - 6, BC=53+6BC = 5\sqrt{3} + 6 and angle ABC=120°ABC = 120°. Find ACAC, giving your answer in the form aba\sqrt{b} where aa and bb are integers greater than 1.

(b)

You are given that cos30°=32\cos 30° = \frac{\sqrt{3}}{2}, sin30°=12\sin 30° = \frac{1}{2} and tan30°=13\tan 30° = \frac{1}{\sqrt{3}}.

In the triangle PQRPQR, PQ=3+25PQ = 3 + 2\sqrt{5} and angle PQR=30°PQR = 30°. Given that the area of this triangle is 2+554\frac{2 + 5\sqrt{5}}{4}, find QRQR, giving your answer in the form c+d5c + d\sqrt{5}, where cc and dd are integers.

Q22023 May/Jun·P125MMedium

DO NOT USE A CALCULATOR IN THIS QUESTION.

Solve the equation (2+5)x2=4x+3(25)(2 + \sqrt{5})x^2 = 4x + 3(2 - \sqrt{5}), giving your answers in the form a+b5a + b\sqrt{5} where aa and bb are integers.

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Q72023 Oct/Nov·P134MMedium

Solve the equation

6x132x131=06x^{\frac{1}{3}} - 2x^{-\frac{1}{3}} - 1 = 0

Give your answers in exact form.

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Q12022 May/Jun·P113MMedium-Easy

Find constants aa, bb and cc such that

pq23r3(pq1)2r1=paqbrc.\frac{\sqrt{p}q^{\frac{2}{3}}r^{-3}}{\left(pq^{-1}\right)^2 r^{-1}} = p^a q^b r^c.
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Q82022 May/Jun·P112 partsMedium-Easy
(a)

Find the exact coordinates of the points of intersection of the curve y=x2+25x20y = x^2 + 2\sqrt{5}x - 20 and the line y=35x+10y = 3\sqrt{5}x + 10.

(b)

It is given that tanθ=312+3\tan\theta = \frac{\sqrt{3}-1}{2+\sqrt{3}}, for 0<θ<π20 < \theta < \frac{\pi}{2}. Find cosec2θ\operatorname{cosec}^2\theta in the form a+b3a+b\sqrt{3}, where aa and bb are constants.

Q32022 Oct/Nov·P124MMedium-Easy

Write (9p2q)×r3(2p)3q1r5\frac{\sqrt{(9p^2q)} \times r^{-3}}{(2p)^3 q^{-1} \sqrt[5]{r}} in the form kpaqbrck p^a q^b r^c, where kk, aa, bb and cc are constants.

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Q82021 May/Jun·P112 partsMedium
(a)

Show that the coordinates of AA can be written in the form (p+q3,r+s3)(p+q\sqrt{3}, r+s\sqrt{3}), where pp, qq, rr and ss are integers.

(b)

Find the xx-coordinate of the stationary point on the curve, giving your answer in the form a+b3a+b\sqrt{3}, where aa and bb are rational numbers.

Q12021 May/Jun·P123MMedium-Easy

Write (pqr)2r13(p2r)1q3\frac{(pqr)^{-2} r^{\frac{1}{3}}}{(p^2 r)^{-1} q^3} in the form paqbrcp^a q^b r^c, where aa, bb and cc are constants.

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