Mathematics 9709/52 — May/June 2022
Cambridge AS Level · Probability & Statistics 1 · worked solutions for every part, with the mark scheme
Topics Representation of Data · Discrete Random Variables · The Normal Distribution · Permutations and Combinations · Probability
For values of the variable , it is given that
Find the value of .
Approach
Use the linearity of summation: . Since there are values, . Substitute the given values and solve for .
Working
Since there are values, each equal to 200:
Substitute the given values:
Solve:
Answer
n = 32
Walkthrough
The summation symbol adds up all values of the variable. The key property used here is that summation is linear: subtracting 200 from every value can be split into summing the values and then subtracting the sum of 200 taken times. Because there are values, the constant 200 appears times, so . Substituting the two given sums, and , gives . Rearranging: , so . The number of values is therefore 32.
Key Takeaways
- Summation is linear: for a constant and terms, .
- A constant added or subtracted from every value contributes that constant times to the total sum.
- This idea underpins coding data: shifting all values by a constant changes the sum predictably while leaving unchanged.
Common Mistakes
- Forgetting that rather than just 200.
- Sign errors, e.g. writing instead of . The mark scheme condones one sign error but the final answer must still be correct.
- Confusing which sum is given, or substituting the wrong value.
Things to Be Careful About
- The mark scheme requires forming the equation , i.e. .
- Check the arithmetic: and .
- Since counts the number of values, it must be a positive whole number.
The rest of this paper
6 more questions- Q2Discrete Random Variables6M
- Q3Representation of Data7M
- Q4The Normal Distribution7M
- Q5Discrete Random Variables · The Normal Distribution8M
- Q6Permutations and Combinations10M
- Q7Probability9M