Mathematics 9709/63 — May/June 2018
Cambridge AS Level · Probability & Statistics 1 (S1) · worked solutions for every part, with the mark scheme
Topics Discrete Random Variables · Representation of Data · The Normal Distribution · Probability · Permutations and Combinations
The masses in kilograms of 50 children having a medical check-up were recorded correct to the nearest kilogram. The results are shown in the table.
| Mass (kg) | |||||
|---|---|---|---|---|---|
| Frequency | 6 | 12 | 14 | 10 | 8 |
Find which class interval contains the lower quartile.
Approach
Find the lower quartile position using the total frequency, then use cumulative frequencies to identify which class interval contains this value.
Working
Total frequency:
Lower quartile position:
Cumulative frequencies:
The 12.5th value falls in the class interval – since .
Answer
15-19
Walkthrough
First, we calculate the total number of children recorded, which is the sum of all frequencies: . The lower quartile (Q1) is the value below which 25% of the data falls. For 50 data points, the lower quartile position is .
Next, we build up the cumulative frequency table to see where the 12.5th value lies. The first class (10–14) has 6 children, so cumulative frequency is 6. Adding the second class (15–19) with 12 children gives a cumulative frequency of 18. Since , the lower quartile must lie in the 15–19 class interval.
Key Takeaways
- The lower quartile position for data points is .
- Cumulative frequencies help identify which class interval contains a given percentile.
- For grouped data, we can only identify the class interval, not the exact value, of a quartile.
Common Mistakes
- Using instead of for the lower quartile position.
- Forgetting that class boundaries for continuous data are at the half-integers (e.g., 14.5, 19.5), so the class 15–19 has upper boundary 19.5.
- Miscounting cumulative frequencies.
Things to Be Careful About
- The class intervals are –, –, –, –, –. These are continuous intervals with boundaries at .
- The question accepts – or – as the answer.
- The unit (kg) is not required for the mark.
On the grid, draw a histogram to illustrate the data in the table.
Approach
For a histogram with unequal class widths, the vertical axis must represent frequency density (fd = frequency / class width), and bar widths must be proportional to class widths.
Working
Step 1: Calculate class boundaries and class widths.
The class boundaries are at the half-integers:
Step 2: Calculate frequency densities.
Step 3: Draw the histogram.
- Horizontal axis: Mass (kg), from to , with linear scale.
- Vertical axis: Frequency density (fd), from to at least , with linear scale.
- Bar widths in ratio .
- Bar heights equal to the frequency densities: .
- Bars are drawn without gaps, starting from .
Answer
Histogram with frequency densities and class widths .
Histogram with fd = 1.2, 2.4, 2.8, 1.0, 0.32 and bar widths 5, 5, 5, 10, 25
Walkthrough
When drawing a histogram for grouped data with unequal class widths, the key principle is that the area of each bar must be proportional to the frequency. This means:
- Bar width = class width
- Bar height = frequency density = frequency / class width
- Area = width × height = class width × (frequency / class width) = frequency
Step 1: Identify the class boundaries. Since the data is continuous (masses recorded to the nearest kg), the boundaries are at the half-integers: 9.5, 14.5, 19.5, 24.5, 34.5, 59.5.
Step 2: Calculate the class widths:
- 10–14:
- 15–19:
- 20–24:
- 25–34:
- 35–59:
Step 3: Calculate the frequency densities (fd = frequency / class width):
Step 4: Draw the histogram on the grid:
- The horizontal axis must be labelled "Mass (kg)" and range from at least 9.5 to 59.5 with a linear scale.
- The vertical axis must be labelled "fd" (or "frequency density") and range from 0 to at least 3, with a linear scale and at least 3 equally spaced values marked.
- Draw five bars with no gaps between them, starting at x = 9.5.
- The first four bars have equal width (proportional to 5), and the last two have widths in ratio 10:25 = 2:5 relative to the first.
- The heights are 1.2, 2.4, 2.8, 1.0, and 0.32 respectively.
Key Takeaways
- For histograms with unequal class widths, always use frequency density on the vertical axis.
- Frequency density = frequency / class width.
- Bar widths must be proportional to class widths, and bars must have no gaps.
- The horizontal axis must start at the lower class boundary (9.5), not at zero, unless a break is indicated.
Common Mistakes
- Using frequency instead of frequency density on the vertical axis (this gives incorrect bar heights for unequal class widths).
- Forgetting that the class 35–59 has width 25, not 24 or 20.
- Drawing bars with gaps between them (histograms for continuous data have no gaps).
- Starting the horizontal axis at 0 without indicating a break, when the data starts at 9.5.
- Not labelling both axes correctly (must include "Mass (kg)" and "fd" or "frequency density").
Things to Be Careful About
- The class widths are 5, 5, 5, 10, 25 — these are not equal, so frequency density must be used.
- The horizontal axis must range from at least 9.5 to 59.5. If it starts from zero, a break in the scale must be indicated.
- The vertical axis must be linear with at least 3 equally spaced values marked.
- At least 3 linearly spaced values must appear on each axis for full marks.
The rest of this paper
6 more questions- Q2The Normal Distribution · Discrete Random Variables6M
- Q3Probability6M
- Q4Representation of Data7M
- Q5Discrete Random Variables · Probability8M
- Q6The Normal Distribution · Discrete Random Variables8M
- Q7Permutations and Combinations10M
