9709/11

Mathematics 9709/11May/June 2013

Cambridge AS Level · Pure Mathematics 1 · worked solutions for every part, with the mark scheme

10
questions
75
marks
105
minutes

Topics Quadratics · Differentiation · Series · Coordinate Geometry · Integration · Circular Measure · +2 more

Q13MDifferentiationFree sample

It is given that f(x)=(2x5)3+xf(x) = (2x - 5)^3 + x, for xRx \in \mathbb{R}. Show that ff is an increasing function.

DifficultyMedium-Easy
Worked solution

Approach

To show that ff is an increasing function, we show that its derivative is positive for all real xx. We differentiate using the chain rule, then use the fact that a square is always non-negative.

Working

Differentiate f(x)=(2x5)3+xf(x) = (2x-5)^3 + x:

f(x)=3(2x5)22+1=6(2x5)2+1f'(x) = 3(2x-5)^2 \cdot 2 + 1 = 6(2x-5)^2 + 1

Equivalently,

f(x)=24(x52)2+1f'(x) = 24\left(x - \frac{5}{2}\right)^2 + 1

For all real xx, (2x5)20(2x-5)^2 \ge 0, so 6(2x5)206(2x-5)^2 \ge 0. Hence

f(x)=6(2x5)2+11>0f'(x) = 6(2x-5)^2 + 1 \ge 1 > 0

Since f(x)>0f'(x) > 0 for every xRx \in \mathbb{R}, the function ff is increasing.

Answer

f(x)=6(2x5)2+1>0f'(x) = 6(2x-5)^2 + 1 > 0 for all real xx, so ff is an increasing function.

Final answer

f'(x) = 6(2x-5)^2 + 1 > 0 for all real x, so f is an increasing function.

Detailed explanation

Walkthrough

To decide whether a function is increasing, we look at its derivative. If f(x)>0f'(x) > 0 for every value in the domain, then the gradient of the curve is always positive, so the function is increasing.

First, differentiate (2x5)3(2x-5)^3. This is a composite function: the outer function is u3u^3 and the inner function is u=2x5u = 2x-5. By the chain rule, the derivative is 3(2x5)23(2x-5)^2 multiplied by the derivative of 2x52x-5, which is 22. So the derivative of (2x5)3(2x-5)^3 is 6(2x5)26(2x-5)^2. Then add the derivative of xx, which is 11, giving

f(x)=6(2x5)2+1.f'(x) = 6(2x-5)^2 + 1.

Now observe that (2x5)2(2x-5)^2 is a square, so it is always greater than or equal to zero. Multiplying by 66 keeps it non-negative. Adding 11 makes the whole expression strictly positive:

6(2x5)2+11>0.6(2x-5)^2 + 1 \ge 1 > 0.

Therefore the gradient is positive for every real xx, so ff is increasing. It is important to argue generally, not just to test a few values.

Key Takeaways

  • A function is increasing on an interval when its derivative is positive throughout that interval.
  • The chain rule is essential for differentiating expressions like (ax+b)n(ax+b)^n: multiply by the power, reduce the power by one, then multiply by the derivative of the inside.
  • A squared term is always non-negative, which is often the key to proving that a derivative is positive.

Common Mistakes

  • Forgetting to multiply by the derivative of the inner function 2x52x-5, giving the incorrect derivative 3(2x5)2+13(2x-5)^2 + 1.
  • Substituting particular values of xx to "show" the function is increasing. The mark scheme explicitly says this is not accepted; you must show the derivative is positive for all xx.
  • Claiming the derivative is non-negative without noting that the +1+1 makes it strictly positive. While 0\ge 0 is allowed, the conclusion that ff is increasing follows most clearly from f(x)>0f'(x) > 0.

Things to Be Careful About

  • The derivative should be written as 6(2x5)2+16(2x-5)^2 + 1 or equivalently 24(x52)2+124\left(x - \frac{5}{2}\right)^2 + 1. Both forms make the positivity clear.
  • The mark scheme awards one mark for 3(2x5)23(2x-5)^2 and one mark for the multiplication by 22 plus the +1+1. Make sure both parts are shown.
  • The domain is all real numbers, so the argument must hold for every real xx, not just for a restricted interval.
Techniques used
differentiate a composite power using the chain ruledetermine the sign of the derivative to prove monotonicity

The rest of this paper

9 more questions
  • Q2Series · Quadratics5M
  • Q3Circular Measure5M
  • Q4Series6M
  • Q5Trigonometry7M
  • Q6Coordinate Geometry7M
  • Q7Quadratics9M
  • Q8Quadratics · Functions10M
  • Q9Differentiation · Quadratics · Integration11M
  • Q10Differentiation · Coordinate Geometry · Integration12M
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