9709/52

Mathematics 9709/52May/June 2022

Cambridge A-Level · Probability & Statistics 1 · worked solutions for every part, with the mark scheme

7
questions
50
marks
75
minutes

Topics Representation of Data · Discrete Random Variables · The Normal Distribution · Permutations and Combinations · Probability

Q13MRepresentation of DataFree sample

For nn values of the variable xx, it is given that

Σ(x200)=446andΣx=6846.\Sigma(x - 200) = 446 \quad \text{and} \quad \Sigma x = 6846.

Find the value of nn.

DifficultyMedium-Easy
Worked solution

Approach

Use the linearity of summation: (x200)=x200\sum(x - 200) = \sum x - \sum 200. Since there are nn values, 200=200n\sum 200 = 200n. Substitute the given values and solve for nn.

Working

(x200)=x200\sum(x - 200) = \sum x - \sum 200

Since there are nn values, each equal to 200:

200=200n\sum 200 = 200n

Substitute the given values:

446=6846200n446 = 6846 - 200n

Solve:

200n=6846446=6400200n = 6846 - 446 = 6400 n=6400200=32n = \frac{6400}{200} = 32

Answer

n=32n = 32
Final answer

n = 32

Detailed explanation

Walkthrough

The summation symbol \sum adds up all nn values of the variable. The key property used here is that summation is linear: subtracting 200 from every value can be split into summing the xx values and then subtracting the sum of 200 taken nn times. Because there are nn values, the constant 200 appears nn times, so 200=200n\sum 200 = 200n. Substituting the two given sums, (x200)=446\sum(x - 200) = 446 and x=6846\sum x = 6846, gives 446=6846200n446 = 6846 - 200n. Rearranging: 200n=6846446=6400200n = 6846 - 446 = 6400, so n=6400200=32n = \frac{6400}{200} = 32. The number of values is therefore 32.

Key Takeaways

  • Summation is linear: for a constant cc and nn terms, (xc)=xcn\sum(x - c) = \sum x - cn.
  • A constant added or subtracted from every value contributes that constant nn times to the total sum.
  • This idea underpins coding data: shifting all values by a constant changes the sum predictably while leaving nn unchanged.

Common Mistakes

  • Forgetting that 200=200n\sum 200 = 200n rather than just 200.
  • Sign errors, e.g. writing 446=6846+200n446 = 6846 + 200n instead of 446=6846200n446 = 6846 - 200n. The mark scheme condones one sign error but the final answer must still be correct.
  • Confusing which sum is given, or substituting the wrong value.

Things to Be Careful About

  • The mark scheme requires forming the equation x200=(x200)\sum x - \sum 200 = \sum(x - 200), i.e. 6846200n=4466846 - 200n = 446.
  • Check the arithmetic: 6846446=64006846 - 446 = 6400 and 6400÷200=326400 \div 200 = 32.
  • Since nn counts the number of values, it must be a positive whole number.
Techniques used
expand the summation of a coded variableapply the linearity of summationsolve a linear equation

The rest of this paper

6 more questions
  • Q2Discrete Random Variables6M
  • Q3Representation of Data7M
  • Q4The Normal Distribution7M
  • Q5Discrete Random Variables · The Normal Distribution8M
  • Q6Permutations and Combinations10M
  • Q7Probability9M
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