9709/71

Mathematics 9709/71May/June 2010

Cambridge A-Level · Probability & Statistics 2 · worked solutions for every part, with the mark scheme

7
questions
50
marks
75
minutes

Topics Continuous Random Variables · Sampling and Estimation · Hypothesis Tests · Linear Combinations of Random Variables · The Poisson Distribution

Q1Continuous Random VariablesFree sample

Fred arrives at random times on a station platform. The times in minutes he has to wait for the next train are modelled by the continuous random variable for which the probability density function ff is shown above.

(i)

State the value of kk.

1M
DifficultyEasy
Worked solution

Approach

The total area under any probability density function must equal 1. Since the graph is a rectangle, we can calculate the area as width times height.

Working

Area=12×k=1\text{Area} = 12 \times k = 1

Solving for kk:

k=112k = \frac{1}{12}

Answer

k=112k = \frac{1}{12}
Final answer

1/12

Detailed explanation

Walkthrough

A fundamental property of any probability density function (PDF) is that the total area under the curve must equal 1, representing the total probability of all possible outcomes. Here, the PDF is a rectangle with width 12 (from t=0t=0 to t=12t=12) and height kk. Setting the area 12k12k equal to 1 gives k=1/12k = 1/12.

Key Takeaways

  • The total area under a PDF is always 1.
  • For a uniform distribution (constant PDF), the height is 1/(ba)1/(b-a) where [a,b][a, b] is the range.

Common Mistakes

  • Forgetting that the total probability must be 1.
  • Using the wrong width for the rectangle.

Things to Be Careful About

  • Ensure the units are consistent. Here tt is in minutes, so the area is in minutes ×\times (1/min) = dimensionless, which is correct for probability.
Techniques used
apply the property that total area under PDF is 1calculate the constant k
(ii)

Explain briefly what this graph tells you about the arrival times of trains.

1M
DifficultyEasy
Worked solution

Approach

The probability density function is constant (f(t)=kf(t) = k) for 0t120 \leq t \leq 12. This indicates a uniform distribution, meaning the waiting time is equally likely to be any value in this range. This implies that trains arrive at regular, fixed intervals.

Working

Since the maximum waiting time is 12 minutes and the distribution is uniform (constant probability density), trains must arrive every 12 minutes. If they arrived less frequently, the waiting time could exceed 12 minutes. If they arrived more frequently, the waiting time range would be smaller.

Answer

Trains arrive every 12 minutes.

Final answer

Trains arrive every 12 minutes

Detailed explanation

Walkthrough

The graph shows a uniform distribution for the waiting time tt between 0 and 12 minutes. A uniform distribution means that every waiting time in this range is equally likely. In a real-world scenario like train arrivals, a uniform waiting time distribution typically arises when trains run on a fixed schedule at regular intervals. Since the waiting time ranges from 0 (arriving just as the train leaves) to 12 (arriving just after the previous train left), the interval between trains must be 12 minutes.

Key Takeaways

  • A uniform PDF implies equally likely outcomes within a range.
  • In transport contexts, a uniform waiting time suggests regular, fixed-interval scheduling.

Common Mistakes

  • Stating 'trains arrive randomly' (this is a uniform distribution, not necessarily random arrival times of trains, but random arrival of the passenger). The question says 'Fred arrives at random times', which leads to the uniform waiting time if trains are on a fixed schedule.

Things to Be Careful About

  • The mark scheme requires the phrase 'every 12 minutes'. Simply stating 'trains arrive at 12 minute intervals' is also acceptable, but the key is the regularity and the 12-minute period.
Techniques used
interpret uniform distributionrelate waiting time to train frequency

The rest of this paper

6 more questions
  • Q2Sampling and Estimation7M
  • Q3Sampling and Estimation · Hypothesis Tests7M
  • Q4Linear Combinations of Random Variables8M
  • Q5Continuous Random Variables8M
  • Q6The Poisson Distribution · Linear Combinations of Random Variables8M
  • Q7Hypothesis Tests · The Poisson Distribution10M
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