9702/33

Physics 9702/33May/June 2011

Cambridge AS Level · Advanced Practical Skills · worked solutions for every part, with the mark scheme

2
questions
40
marks
120
minutes

Topics Manipulation, Measurement and Observation · Presentation of Data and Observations · Analysis, Conclusions and Evaluation

Q1Manipulation, Measurement and ObservationPresentation of Data and ObservationsAnalysis, Conclusions and EvaluationFree sample

In this experiment you will investigate how the motion of a paper strip depends on its width.

(a)
(i)

Measure and record the width xx of the thin paper strip, as shown in Fig. 1.1.

xx = ______ cm\text{cm}

1M
(ii)

Connect the clips to the strip, as shown in Fig. 1.2.

(b)
(i)

Set up the apparatus with the top clip supported on the nail, as shown in Fig. 1.3.

(ii)

Twist the wooden rod through an angle of approximately 4545^{\circ} in a horizontal plane, as shown in Fig. 1.4.

Release the rod and watch its movement.
The wooden rod completes one swing by twisting one way and then back the other way, as shown in Fig. 1.4.
The time taken for each complete swing is TT.
By timing several of these complete swings, determine an accurate value for TT.

TT = ______ s\text{s}

2M
(c)

By cutting new strips from the graph paper, repeat (a) and (b) until you have six sets of values of xx and TT. Values of xx should be in the range 1 cmx6 cm1\ \text{cm} \leq x \leq 6\ \text{cm}.

Include values of 1x\frac{1}{x} in your table of results.

9M
(d)
(i)

Plot a graph of TT on the yy-axis against 1x\frac{1}{x} on the xx-axis.

3M
(ii)

Draw the straight line of best fit.

1M
(iii)

Determine the gradient and yy-intercept of this line.

gradient = ______
yy-intercept = ______

2M
(e)

It is suggested that the relationship between TT and xx is

T=ax+bT = \frac{a}{x} + b

where aa and bb are constants.

Using your answers from (d)(iii), determine the values of aa and bb.
Give appropriate units.

aa = ______
bb = ______

1M
(f)

State one problem with determining an experimental value of TT for x=15 cmx = 15\ \text{cm}.

1M

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