9701/12

Chemistry 9701/12October/November 2023

Cambridge AS Level · answer key with instant marking and worked solutions

40
questions
40
marks
75
minutes

Topics Atoms, Molecules and Stoichiometry · Atomic Structure · Chemical Bonding · Introduction to Organic Chemistry · Electrochemistry · States of Matter · +13 more

Tap an option under each question to check it — your score builds as you go.

Q11MAtomic StructureFree sample

Which particle contains 8 protons, 9 neutrons and 10 electrons?

Options

A   816O^{16}_8\text{O}^-
B   816O2^{16}_8\text{O}^{2-}
C   817O^{17}_8\text{O}^-
D   817O2^{17}_8\text{O}^{2-}

DifficultyEasy
Worked solution

Working

  • 8 protons \Rightarrow atomic number Z=8Z = 8 (oxygen).
  • Mass number A=A = protons + neutrons =8+9=17= 8 + 9 = 17.
  • 10 electrons means 2 more electrons than protons \Rightarrow charge 22-.

So the particle is 817O2^{17}_8\text{O}^{2-}.

Answer

D (817O2^{17}_8\text{O}^{2-})

Final answer

D

Detailed explanation

Background Concept

Atoms are represented by the notation ZAXcharge^{A}_{Z}\text{X}^{\text{charge}}, where:

  • ZZ (subscript) is the atomic number, equal to the number of protons. It identifies the element.
  • AA (superscript) is the mass number, equal to the total number of protons and neutrons.
  • The charge, written top right, is the number of protons minus the number of electrons.

In a neutral atom, the number of electrons equals the number of protons. A negative ion has more electrons than protons; a positive ion has fewer.

Understanding the Question

The question gives the composition of a particle: 8 protons, 9 neutrons and 10 electrons. We must choose the correct notation from four oxygen species. The options differ in mass number (16 or 17) and charge (- or 22-). To answer, we need to work out the atomic number, mass number and charge from the particle counts.

Approach

  1. Use the proton number to identify the element: 8 protons means Z=8Z = 8, which is oxygen.
  2. Add protons and neutrons to get the mass number: 8+9=178 + 9 = 17.
  3. Compare electrons with protons to find the charge: 10 electrons vs 8 protons gives a 22- charge.
  4. Match these three pieces of information to the options.

Step-by-Step Reasoning

  • Protons: 8 protons means the atomic number is 8, so the element is oxygen, symbol O.
  • Neutrons: 9 neutrons. Mass number A=A = protons + neutrons =8+9=17= 8 + 9 = 17. This eliminates options A and B, which both have mass number 16.
  • Electrons: A neutral oxygen atom has 8 electrons. This particle has 10 electrons, which is 2 more than the number of protons. Therefore the charge is 22-.
  • The correct notation is therefore 817O2^{17}_8\text{O}^{2-}, which is option D.

Why the other options are wrong:

  • A 816O^{16}_8\text{O}^- has 8 protons, 8 neutrons and 9 electrons. It has the wrong mass number and the wrong charge.
  • B 816O2^{16}_8\text{O}^{2-} has 8 protons, 8 neutrons and 10 electrons. It has the wrong mass number.
  • C 817O^{17}_8\text{O}^- has 8 protons, 9 neutrons and 9 electrons. It has the correct mass number but the wrong charge.

Key Takeaways

  • In nuclear notation, the superscript is the mass number and the subscript is the atomic number.
  • Mass number = protons + neutrons.
  • Charge = protons - electrons. A negative ion has more electrons than protons.

Common Mistakes

  • Confusing mass number with atomic number: 16 is not the mass number when there are 9 neutrons.
  • Thinking that 10 electrons means a 11- charge. The charge must be found by comparing the electron count with the proton count, not by counting electrons alone.
  • Mixing up the superscript and subscript positions in the notation.

Things to Be Careful About

  • Always read the superscript as the mass number and the subscript as the atomic number.
  • For an ion, the charge sign matters: 10 electrons and 8 protons gives 22-, not 2+2+.
  • Check that the mass number equals protons plus neutrons, not just the number written in the option.
Techniques used
deduce the atomic number from the proton countcalculate the mass number from protons and neutronsdeduce the ionic charge from the electron count

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