Chemistry 9701/11 — October/November 2023
Cambridge AS Level · Multiple Choice (AS Level) · answer key with instant marking and worked solutions
Topics Atoms, Molecules and Stoichiometry · Chemical Bonding · Atomic Structure · Introduction to Organic Chemistry · Carbonyl Compounds · Chemical Energetics · +14 more
Tap an option under each question to check it — your score builds as you go.
Sodium azide, , is an explosive used to inflate airbags in cars when they crash. It consists of positive sodium ions and negative azide ions.
What are the numbers of electrons in the sodium ion and the azide ion?
Options
| sodium ion | azide ion | |
|---|---|---|
| A | 10 | 20 |
| B | 10 | 22 |
| C | 12 | 20 |
| D | 12 | 22 |
Working
Sodium has proton number 11. The sodium ion has lost one electron, so it contains electrons.
The azide ion is . Each nitrogen atom has proton number 7, so three nitrogen atoms contribute protons. The single negative charge means one extra electron, giving electrons.
Answer
B (sodium ion 10, azide ion 22)
B
Background Concept
A neutral atom contains equal numbers of protons and electrons. The number of protons is the proton number (atomic number), which is unique to each element. When an atom forms an ion, it either loses electrons (forming a positive ion) or gains electrons (forming a negative ion). For a polyatomic ion, the total number of electrons is found by adding the electrons of all atoms in the ion and then adjusting for the overall charge: a negative charge means extra electrons, a positive charge means fewer electrons.
Understanding the Question
This question asks for the number of electrons in two ions present in sodium azide: the sodium ion and the azide ion. The formula tells us the compound contains and . We are given four pairs of numbers and must select the correct pair. The key is to recall the proton numbers of sodium and nitrogen and then apply the ionic charges correctly.
Approach
First, identify the proton numbers of the elements involved: sodium is 11 and nitrogen is 7. For a monatomic ion, subtract the positive charge from the proton number. For a polyatomic ion, multiply the proton number of each atom by the number of atoms, then add electrons for each negative charge (or subtract for each positive charge).
Step-by-Step Reasoning
- Sodium atom: proton number = 11, so a neutral sodium atom has 11 electrons.
- The sodium ion is , meaning it has lost one electron: electrons.
- Azide ion: formula , containing three nitrogen atoms.
- Each nitrogen atom has proton number 7, so three nitrogen atoms contribute protons, and a neutral unit would have 21 electrons.
- The charge means one extra electron has been gained: electrons.
- Therefore the correct pair is sodium ion = 10, azide ion = 22, which is option B.
Distractors: Option A gives azide as 20, which might come from forgetting the extra electron or miscounting the nitrogen atoms. Option C gives sodium as 12, which would mean adding an electron to a neutral sodium atom instead of removing one. Option D combines both errors.
Key Takeaways
- The number of electrons in an ion is the total proton number adjusted by the ionic charge.
- For a polyatomic ion, sum the electrons of all atoms, then adjust for the overall charge.
- A positive charge means electrons lost; a negative charge means electrons gained.
Common Mistakes
- Using the mass number instead of the proton number when counting electrons.
- Adding an electron for a positive ion or removing one for a negative ion.
- Forgetting that the azide ion contains three nitrogen atoms and carries a single negative charge.
Things to Be Careful About
- Always use the proton number (atomic number), not the mass number, when counting electrons.
- Check the sign of the ionic charge carefully: has fewer electrons than , while has more electrons than three neutral nitrogen atoms.
- In a polyatomic ion, the charge applies to the whole ion, so adjust the total electron count by the magnitude of the charge.
The rest of this paper
39 more questions- Q2Atomic Structure1M
- Q3Atoms, Molecules and Stoichiometry1M
- Q4Atoms, Molecules and Stoichiometry1M
- Q5Chemical Bonding1M
- Q6Chemical Bonding1M
- Q7States of Matter · Atoms, Molecules and Stoichiometry1M
- Q8Chemical Bonding1M
- Q9Chemical Energetics1M
- Q10Chemical Energetics1M
- Q11Electrochemistry1M
- Q12Equilibria1M
- Q13Equilibria1M
- Q14Reaction Kinetics1M
- Q15Chemical Energetics · Reaction Kinetics1M
- Q16Atomic Structure · Chemical Periodicity1M
- Q17Chemical Periodicity · Atomic Structure1M
- Q18Chemical Periodicity1M
- Q19Group 2 · Electrochemistry1M
- Q20Group 21M
- Q21Group 2 · Atoms, Molecules and Stoichiometry1M
- Q22Chemical Bonding · Group 171M
- Q23Group 171M
- Q24Atoms, Molecules and Stoichiometry1M
- Q25Atoms, Molecules and Stoichiometry · Introduction to Organic Chemistry1M
- Q26Introduction to Organic Chemistry1M
- Q27Chemical Bonding1M
- Q28Hydrocarbons1M
- Q29Hydrocarbons · Atoms, Molecules and Stoichiometry1M
- Q30Carbonyl Compounds · Introduction to Organic Chemistry1M
- Q31Halogen Compounds1M
- Q32Organic Synthesis · Nitrogen Compounds1M
- Q33Hydroxy Compounds1M
- Q34Hydroxy Compounds1M
- Q35Hydroxy Compounds1M
- Q36Carbonyl Compounds1M
- Q37Carbonyl Compounds · Introduction to Organic Chemistry1M
- Q38Carboxylic Acids and Derivatives1M
- Q39Analytical Techniques1M
- Q40Analytical Techniques · Carbonyl Compounds1M