9701/21

Chemistry 9701/21October/November 2016

Cambridge AS Level · AS Level Structured Questions · worked solutions for every part, with the mark scheme

5
questions
60
marks
75
minutes

Topics Atoms, Molecules and Stoichiometry · Introduction to Organic Chemistry · Group IV (Group 14) · Chemical Energetics · Atomic Structure · Group 2 · +4 more

Q1Atoms, Molecules and StoichiometryGroup IV (Group 14)Free sample

A 0.17 g0.17\text{ g} sample of a Group 14 chloride, XCl4\text{XCl}_4, reacted with water to produce an oxide, XO2\text{XO}_2, and HCl\text{HCl}.

equation 1 XCl4(s)+2H2O(l)XO2(s)+4HCl(aq)\quad \text{XCl}_4(\text{s}) + 2\text{H}_2\text{O}(\text{l}) \rightarrow \text{XO}_2(\text{s}) + 4\text{HCl}(\text{aq})

The HCl\text{HCl} produced was absorbed in 100 cm3100\text{ cm}^3 of 0.10 moldm30.10\text{ mol}\,\text{dm}^{-3} sodium hydroxide solution (an excess).

In a titration, the unreacted sodium hydroxide solution required 30.0 cm330.0\text{ cm}^3 of 0.20 moldm30.20\text{ mol}\,\text{dm}^{-3} hydrochloric acid for complete neutralisation.

(a)

Calculate the amount, in moles, of hydrochloric acid used in the titration to neutralise the unreacted sodium hydroxide solution.

amount=............................ mol\text{amount} = \text{............................ mol}
1M
(b)

Write the equation for the reaction between hydrochloric acid and sodium hydroxide.

1M
(c)

Calculate the amount, in moles, of sodium hydroxide neutralised in the titration.

amount=............................ mol\text{amount} = \text{............................ mol}
1M
(d)

Calculate the amount, in moles, of sodium hydroxide that reacted with the HCl\text{HCl} produced by the reaction in equation 1.

amount=............................ mol\text{amount} = \text{............................ mol}
1M
(e)

Calculate the amount, in moles, of HCl\text{HCl} produced by the reaction in equation 1.

amount=............................ mol\text{amount} = \text{............................ mol}
1M
(f)

Calculate the amount, in moles, of XCl4\text{XCl}_4 in the original 0.17 g0.17\text{ g} sample.

amount=............................ mol\text{amount} = \text{............................ mol}
1M
(g)

Calculate the molecular mass, MrM_{\text{r}}, of XCl4\text{XCl}_4.

Mr=............................M_{\text{r}} = \text{............................}
1M
(h)

Calculate the relative atomic mass, ArA_{\text{r}}, of X\text{X} and suggest its identity.

Ar of X=............................identity of X.............................................\begin{aligned} A_{\text{r}} \text{ of X} &= \text{............................} \\ \text{identity of X} &\quad \text{.............................................} \end{aligned}
2M

The rest of this paper

4 more questions
  • Q2Chemical Energetics · Atoms, Molecules and Stoichiometry13M
  • Q3Atomic Structure · Group 2 · Equilibria14M
  • Q4Introduction to Organic Chemistry · Hydrocarbons · Polymerisation18M
  • Q5Introduction to Organic Chemistry · Hydroxy Compounds6M
Loading the full paper…