9701/43

Chemistry 9701/43May/June 2022

Cambridge A-Level · A Level Structured Questions · worked solutions for every part, with the mark scheme

7
questions
100
marks
120
minutes

Topics Electrochemistry · Introduction to A Level Organic Chemistry · Equilibria · Transition Elements · Hydrocarbons · Carboxylic Acids and Derivatives · +7 more

Q1Group 2EquilibriaChemical EnergeticsFree sample
(a)

The solubility of the Group 2 sulfates decreases down the group.

Explain this trend.

3M
(b)

Describe what is observed when magnesium and barium are reacted separately with an excess of dilute sulfuric acid.

magnesium

barium

1M
(c)

The solubility product, KspK_{\text{sp}}, of BaSO4\text{BaSO}_4 is 1.08×1010 mol2dm61.08 \times 10^{-10}\text{ mol}^2\text{dm}^{-6} at 298 K298\text{ K}.

Calculate the solubility of BaSO4\text{BaSO}_4 in g per 100cm3\text{g per } 100\text{cm}^3 of solution.

solubility of BaSO4=\text{BaSO}_4 = .............................. g per 100cm3 of solution\text{g per } 100\text{cm}^3\text{ of solution}

2M
(d)
(i)

The equation for the formation of a gaseous sulfate ion is shown.

S(s)+2O2(g)+2eSO42(g)ΔH=ΔHf of SO42(g)\text{S(s)} + 2\text{O}_2(\text{g}) + 2\text{e}^- \rightarrow \text{SO}_4^{2-}(\text{g}) \quad \Delta H = \Delta H_{\text{f}}^\ominus \text{ of } \text{SO}_4^{2-}(\text{g})

Calculate the standard enthalpy change of formation, ΔHf\Delta H_{\text{f}}^\ominus, of SO42(g)\text{SO}_4^{2-}(\text{g}). It may be helpful to draw a labelled energy cycle. Use relevant data from Table 1.1 in your calculations.

Table 1.1

energy changevalue / kJ mol1\text{kJ}\text{ mol}^{-1}
lattice energy of barium sulfate, BaSO4(s)\text{BaSO}_4(\text{s})2469-2469
standard enthalpy change of formation of barium sulfate1473-1473
standard enthalpy change of atomisation of barium+180+180
first ionisation energy of barium+503+503
second ionisation energy of barium+965+965
standard enthalpy change of atomisation of sulfur+279+279
standard enthalpy change for S(g)S2(g)\text{S(g)} \rightarrow \text{S}^{2-}(\text{g})+440+440
standard enthalpy change for O(g)O2(g)\text{O(g)} \rightarrow \text{O}^{2-}(\text{g})+657+657
O=O\text{O=O} bond energy+496+496

ΔHf of SO42(g)=\Delta H_{\text{f}}^\ominus \text{ of } \text{SO}_4^{2-}(\text{g}) = .............................. kJ mol1\text{kJ}\text{ mol}^{-1}

3M
(ii)

Suggest how the lattice energy of BaSO4(s)\text{BaSO}_4(\text{s}) differs from the lattice energy of Cs2SO4(s)\text{Cs}_2\text{SO}_4(\text{s}). Explain your answer.

2M
(e)

The reaction of solid hydrated barium hydroxide, Ba(OH)28H2O\text{Ba(OH)}_2\cdot 8\text{H}_2\text{O}, with ammonium salts is endothermic.

(i)

Calculate the minimum temperature at which the reaction of Ba(OH)28H2O\text{Ba(OH)}_2\cdot 8\text{H}_2\text{O} with NH4NO3\text{NH}_4\text{NO}_3 becomes feasible. Show all your working.

Ba(OH)28H2O(s)+2NH4NO3(s)2NH3(g)+Ba(NO3)2(s)+10H2O(l)ΔHr=+132 kJ mol1ΔS=+616 J K1mol1\begin{aligned} \text{Ba(OH)}_2\cdot 8\text{H}_2\text{O(s)} + 2\text{NH}_4\text{NO}_3(\text{s}) &\rightarrow 2\text{NH}_3(\text{g}) + \text{Ba(NO}_3)_2(\text{s}) + 10\text{H}_2\text{O(l)} & \Delta H_r^\ominus &= +132\text{ kJ}\text{ mol}^{-1} \\ & & \Delta S^\ominus &= +616\text{ J}\text{ K}^{-1}\text{mol}^{-1} \end{aligned}

temperature = .............................. C^\circ\text{C}

2M
(ii)

Barium hydroxide reacts readily with ammonium chloride on mixing at room temperature.

Ba(OH)28H2O(s)+2NH4Cl(s)2NH3(g)+BaCl22H2O(s)+8H2O(l)ΔHr=+133 kJ mol1\text{Ba(OH)}_2\cdot 8\text{H}_2\text{O(s)} + 2\text{NH}_4\text{Cl(s)} \rightarrow 2\text{NH}_3(\text{g}) + \text{BaCl}_2\cdot 2\text{H}_2\text{O(s)} + 8\text{H}_2\text{O(l)} \quad \Delta H_r^\ominus = +133\text{ kJ}\text{ mol}^{-1}

Some relevant standard entropies are given in Table 1.2.

Table 1.2

substanceBa(OH)28H2O(s)\text{Ba(OH)}_2\cdot 8\text{H}_2\text{O(s)}NH4Cl(s)\text{NH}_4\text{Cl(s)}NH3(g)\text{NH}_3(\text{g})BaCl22H2O(s)\text{BaCl}_2\cdot 2\text{H}_2\text{O(s)}H2O(l)\text{H}_2\text{O(l)}
S/J K1mol1S^\ominus / \text{J}\text{ K}^{-1}\text{mol}^{-1}42742795951921922032037070

Calculate the standard Gibbs free energy change, ΔG\Delta G^\ominus, for this reaction at 25C25^\circ\text{C}.

ΔG=\Delta G^\ominus = .............................. kJ mol1\text{kJ}\text{ mol}^{-1}

3M

The rest of this paper

6 more questions
  • Q2Transition Elements · Electrochemistry13M
  • Q3Reaction Kinetics · Electrochemistry15M
  • Q4Transition Elements · Electrochemistry · Introduction to A Level Organic Chemistry · Hydrocarbons14M
  • Q5Carboxylic Acids and Derivatives · Polymerisation16M
  • Q6Introduction to A Level Organic Chemistry · Analytical Techniques · Nitrogen Compounds · Polymerisation12M
  • Q7Introduction to A Level Organic Chemistry · Nitrogen Compounds · Analytical Techniques · Hydrocarbons · Organic Synthesis · Carboxylic Acids and Derivatives · Equilibria14M
Loading the full paper…