9701/42

Chemistry 9701/42February/March 2019

Cambridge A-Level · A Level Structured Questions · worked solutions for every part, with the mark scheme

7
questions
100
marks
120
minutes

Topics Equilibria · Group 2 · Chemical Energetics · Transition Elements · Organic Synthesis · Carboxylic Acids and Derivatives · +8 more

Q1Group 2Chemical EnergeticsTransition ElementsEquilibriaReaction KineticsFree sample
(a)

State one natural and one man-made occurrence of oxides of nitrogen.

1M
(b)

Under conditions of high pressure and a catalyst, nitrogen monoxide, NO\text{NO}, forms two other oxides of nitrogen, dinitrogen monoxide, N2O\text{N}_2\text{O}, and dinitrogen trioxide, N2O3\text{N}_2\text{O}_3.

......NO(g)......N2O(g)+......N2O3(g)ΔH=195.2 kJ mol1,ΔG=102.8 kJ mol1...... \text{NO}(\text{g}) \rightarrow ...... \text{N}_2\text{O}(\text{g}) + ...... \text{N}_2\text{O}_3(\text{g}) \quad \Delta H^\ominus = -195.2 \text{ kJ mol}^{-1}, \quad \Delta G^\ominus = -102.8 \text{ kJ mol}^{-1}
(i)

Balance the equation above for the formation of N2O\text{N}_2\text{O} and N2O3\text{N}_2\text{O}_3 from NO\text{NO}.

1M
(ii)

State how the oxidation number of nitrogen changes during this reaction.

NON2O\text{NO} \rightarrow \text{N}_2\text{O} from ............................... to ...............................

NON2O3\text{NO} \rightarrow \text{N}_2\text{O}_3 from ............................... to ...............................

1M
(iii)

Calculate the entropy change for the reaction at 298 K298\text{ K}. Include the units in your answer.

ΔS=..............................\Delta S^\ominus = \text{..............................} units=..............................\text{units} = \text{..............................}
2M
(iv)

State whether the sign of ΔS\Delta S^\ominus calculated in (iii) agrees with that predicted from your balanced equation in (i). Explain your answer.

1M
(c)

At room temperature N2O3\text{N}_2\text{O}_3 dissociates.

N2O3(g)NO(g)+NO2(g)\text{N}_2\text{O}_3(\text{g}) \rightleftharpoons \text{NO}(\text{g}) + \text{NO}_2(\text{g})
(i)

Write the expression for KpK_p for this equilibrium. Include the units in your answer.

Kp=..............................K_p = \text{..............................} units=..............................\text{units} = \text{..............................}
1M
(ii)

A 1.00 dm31.00\text{ dm}^3 flask at 25C25^\circ\text{C} is filled with pure N2O3(g)\text{N}_2\text{O}_3(\text{g}) at an initial pressure of 0.60 atm0.60\text{ atm}.
At equilibrium, the partial pressure of NO2(g)\text{NO}_2(\text{g}) is 0.48 atm0.48\text{ atm}.

Calculate the partial pressures of NO(g)\text{NO}(\text{g}) and N2O3(g)\text{N}_2\text{O}_3(\text{g}) at equilibrium. Hence calculate the value of KpK_p at 25C25^\circ\text{C}.

p(NO(g))=.........................................p(\text{NO}(\text{g})) = \text{.........................................} p(N2O3(g))=.........................................p(\text{N}_2\text{O}_3(\text{g})) = \text{.........................................} Kp=.........................................K_p = \text{.........................................}
2M
(d)

NO reacts readily with oxygen.

2NO(g)+O2(g)2NO2(g)2\text{NO}(\text{g}) + \text{O}_2(\text{g}) \rightarrow 2\text{NO}_2(\text{g})

The table shows how the initial rate of this reaction at 25C25^\circ\text{C} depends on the initial concentrations of the reactants.

[NO(g)][\text{NO}(\text{g})] / mol dm3\text{mol dm}^{-3}[O2(g)][\text{O}_2(\text{g})] / mol dm3\text{mol dm}^{-3}initial rate / mol dm3 s1\text{mol dm}^{-3}\text{ s}^{-1}
0.1000.05003.50
0.05000.1001.75
0.05000.05000.875
(i)

Deduce the order of reaction with respect to each reactant. Explain your reasoning.

order with respect to [NO(g)][\text{NO}(\text{g})]: ..............................................................................................

order with respect to [O2(g)][\text{O}_2(\text{g})]: ................................................................................................

2M
(ii)

State the rate equation for this reaction. Use the rate equation to calculate the rate constant. Include the units for the rate constant in your answer.

rate=..............................\text{rate} = \text{..............................} rate constant, k=..............................\text{rate constant, } k = \text{..............................} units of k=..............................\text{units of } k = \text{..............................}
3M
(e)

NO reacts with iron pentacarbonyl, Fe(CO)5\text{Fe}(\text{CO})_5, as shown. NO and CO are both monodentate ligands.

Fe(CO)5+2NOFe(CO)2(NO)2+3CO\text{Fe}(\text{CO})_5 + 2\text{NO} \rightarrow \text{Fe}(\text{CO})_2(\text{NO})_2 + 3\text{CO}

During this reaction the co-ordination number of the iron changes.

(i)

State what is meant by the term co-ordination number.

1M
(ii)

Describe how the co-ordination number of the iron changes during this reaction.

from ............................................................... to ...............................................................

1M
(iii)

Only one stereoisomer of Fe(CO)2(NO)2\text{Fe}(\text{CO})_2(\text{NO})_2 exists.

Use this information to suggest the geometry of the complex.

1M
(f)

The complex Ru(NO)L2Cl3\text{Ru}(\text{NO})\text{L}_2\text{Cl}_3 exists in three isomeric forms. L represents the monodentate ligand C6H5P(CH3)2\text{C}_6\text{H}_5\text{P}(\text{CH}_3)_2.

(i)

Complete the three-dimensional diagrams to show the three isomers of Ru(NO)L2Cl3\text{Ru}(\text{NO})\text{L}_2\text{Cl}_3.

2M
(ii)

Suggest the type of isomerism shown.

1M

The rest of this paper

6 more questions
  • Q2Group 2 · Chemical Energetics · Equilibria13M
  • Q3Equilibria7M
  • Q4Transition Elements · Electrochemistry17M
  • Q5Polymerisation · Organic Synthesis · Carboxylic Acids and Derivatives11M
  • Q6Introduction to A Level Organic Chemistry · Equilibria · Nitrogen Compounds · Analytical Techniques15M
  • Q7Carboxylic Acids and Derivatives · Organic Synthesis · Hydrocarbons · Hydroxy Compounds · Nitrogen Compounds17M
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