9701/41

Chemistry 9701/41October/November 2012

Cambridge A-Level · A Level Structured Questions · worked solutions for every part, with the mark scheme

8
questions
100
marks
120
minutes

Topics Introduction to A Level Organic Chemistry · Carboxylic Acids and Derivatives · Nitrogen Compounds · Group 2 · Electrochemistry · Analytical Techniques · +6 more

Q1Group 2ElectrochemistryChemical EnergeticsFree sample
(a)

Write down what you would see, and write equations for the reactions that occur, when silicon(IV) chloride and phosphorus(V) chloride are separately mixed with water.

silicon(IV) chloride

phosphorus(V) chloride

4M
(b)

Iron(III) chloride, FeCl3\text{FeCl}_3, is used to dissolve unwanted copper from printed circuit boards (PCBs) by the following reaction.

2FeCl3(aq)+Cu(s)2FeCl2(aq)+CuCl2(aq)2\text{FeCl}_3(\text{aq}) + \text{Cu}(\text{s}) \rightarrow 2\text{FeCl}_2(\text{aq}) + \text{CuCl}_2(\text{aq})

A solution in which [Fe3+(aq)][\text{Fe}^{3+}(\text{aq})] was originally equal to 1.50 mol dm31.50\text{ mol dm}^{-3} was re-used several times to dissolve copper from the PCBs, and was then titrated as follows.

A 2.50 cm32.50\text{ cm}^3 sample of the partially-used-up solution was acidified and titrated with 0.0200 mol dm30.0200\text{ mol dm}^{-3} KMnO4\text{KMnO}_4.
This oxidised any FeCl2\text{FeCl}_2 in the solution back to FeCl3\text{FeCl}_3.
It was found that 15.0 cm315.0\text{ cm}^3 of KMnO4(aq)\text{KMnO}_4(\text{aq}) was required to reach the end point.

6M
(i)

Construct an ionic equation for the reaction between Fe2+\text{Fe}^{2+} and MnO4\text{MnO}_4^- in acid solution.

(ii)

State here the Fe2+:MnO4\text{Fe}^{2+} : \text{MnO}_4^- ratio from your equation in (i).

(iii)

Calculate the number of moles of MnO4\text{MnO}_4^- used in the titration.

(iv)

Calculate the number of moles of Fe2+\text{Fe}^{2+} in 2.50 cm32.50\text{ cm}^3 of the partially-used-up solution.

(v)

Calculate the [Fe2+][\text{Fe}^{2+}] in the partially-used-up solution.

(vi)

Calculate the mass of copper that could still be dissolved by 100 cm3100\text{ cm}^3 of the partially-used-up solution.

(c)

When SiCl4\text{SiCl}_4 vapour is passed over Si\text{Si} at red heat, Si2Cl6\text{Si}_2\text{Cl}_6 is formed. Si2Cl6\text{Si}_2\text{Cl}_6 contains a Si-Si\text{Si-Si} bond.
The reaction of Si2Cl6\text{Si}_2\text{Cl}_6 and Cl2\text{Cl}_2 re-forms SiCl4\text{SiCl}_4.

Si2Cl6(g)+Cl2(g)2SiCl4(g)\text{Si}_2\text{Cl}_6(\text{g}) + \text{Cl}_2(\text{g}) \rightarrow 2\text{SiCl}_4(\text{g})

Use bond energy data from the Data Booklet to calculate ΔH\Delta H^\ominus for this reaction.

2M
(d)

Calcium forms three calcium silicides, Ca2Si\text{Ca}_2\text{Si}, CaSi\text{CaSi} and CaSi2\text{CaSi}_2. The first of these reacts with water as follows.

.........Ca2Si+........H2O.......Ca(OH)2+......SiO2+.....H2.........\text{Ca}_2\text{Si} + ........\text{H}_2\text{O} \rightarrow .......\text{Ca(OH)}_2 + ......\text{SiO}_2 + .....\text{H}_2
2M
(i)

Balance this equation. You may find the use of oxidation numbers helpful.

(ii)

During this reaction, state

which element(s) have been oxidised,

which element(s) have been reduced.

The rest of this paper

7 more questions
  • Q2Electrochemistry · Equilibria · Group 2 · Analytical Techniques18M
  • Q3Reaction Kinetics10M
  • Q4Introduction to A Level Organic Chemistry · Carboxylic Acids and Derivatives · Nitrogen Compounds · Hydrocarbons10M
  • Q5Hydroxy Compounds · Introduction to A Level Organic Chemistry · Carboxylic Acids and Derivatives · Nitrogen Compounds18M
  • Q6Nitrogen Compounds10M
  • Q7Analytical Techniques10M
  • Q8Polymerisation · Introduction to A Level Organic Chemistry · Carboxylic Acids and Derivatives10M
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