9701/52

Chemistry 9701/52May/June 2012

Cambridge A-Level · Planning, Analysis and Evaluation · worked solutions for every part, with the mark scheme

2
questions
30
marks
75
minutes

Topics Analysis, Conclusions and Evaluation · Planning

Q1PlanningAnalysis, Conclusions and EvaluationFree sample

When ammonium nitrate(V), NH4NO3\text{NH}_4\text{NO}_3, is heated it decomposes completely into nitrogen(I) oxide, N2O\text{N}_2\text{O}, and water vapour, H2O\text{H}_2\text{O}, which if allowed to cool will condense to liquid water.

The stoichiometric equation for this decomposition is

NH4NO3(s)N2O(g)+2H2O(l)\text{NH}_4\text{NO}_3(\text{s}) \rightarrow \text{N}_2\text{O}(\text{g}) + 2\text{H}_2\text{O}(\text{l})

The following information gives some of the hazards associated with ammonium nitrate(V).

Ammonium nitrate(V) NH4NO3\text{NH}_4\text{NO}_3
Oxidising: Contact with combustible material may cause fire. Explosive when mixed with combustible material.
Do not allow the salt to become contaminated with organic matter and do not grind it.

You are to plan an experiment to investigate the molar ratio of nitrogen(I) oxide and ammonium nitrate(V) at 25 C25\text{ }^{\circ}\text{C}, and confirm that it remains unchanged as the mass of ammonium nitrate(V) changes.

(a)
(i)

Predict quantitatively how the number of moles of nitrogen(I) oxide varies as the number of moles of ammonium nitrate(V) increases, if the products are measured at room temperature 25 C25\text{ }^{\circ}\text{C}.

DifficultyEasy
Worked solution

Answer

The number of moles of nitrogen(I) oxide is directly proportional to the number of moles of ammonium nitrate(V), with a 1:1 ratio.

Final answer

The number of moles of nitrogen(I) oxide is directly proportional to the number of moles of ammonium nitrate(V), with a 1:1 ratio.

Detailed explanation

Background Concept

In any chemical reaction, the stoichiometric coefficients in the balanced symbol equation define the exact molar ratios in which reactants are consumed and products are formed. These ratios remain constant regardless of the scale of the reaction, provided the reaction goes to completion.

Understanding the Question

The question asks for a quantitative prediction of how the moles of nitrogen(I) oxide (N2O\text{N}_2\text{O}) produced relate to the moles of ammonium nitrate(V\text{V}) (NH4NO3\text{NH}_4\text{NO}_3) decomposed, measured at 25 C25\text{ }^{\circ}\text{C}.

Approach

Read the balanced equation and extract the molar ratio between the reactant and the specific gaseous product of interest. At 25 C25\text{ }^{\circ}\text{C}, water is a liquid, so only N2O\text{N}_2\text{O} contributes to the gas phase, but the question specifically asks about the moles of N2O\text{N}_2\text{O}, not the total gas moles.

Step-by-Step Reasoning

  1. The balanced equation is NH4NO3(s)N2O(g)+2H2O(l)\text{NH}_4\text{NO}_3(\text{s}) \rightarrow \text{N}_2\text{O}(\text{g}) + 2\text{H}_2\text{O}(\text{l}).
  2. The coefficient for NH4NO3\text{NH}_4\text{NO}_3 is 1, and the coefficient for N2O\text{N}_2\text{O} is 1.
  3. Therefore, 1 mole of NH4NO3\text{NH}_4\text{NO}_3 produces exactly 1 mole of N2O\text{N}_2\text{O}.
  4. This means the relationship is a direct proportionality with a 1:1 ratio. If you double the moles of reactant, you double the moles of N2O\text{N}_2\text{O} produced.

Key Takeaways

Stoichiometric coefficients directly give the molar ratios of reactants and products. Predictions based on these ratios are always linear and pass through the origin.

Common Mistakes

  • Stating the ratio is 1:2 (confusing N2O\text{N}_2\text{O} with H2O\text{H}_2\text{O}).
  • Forgetting to state that the relationship is 'directly proportional' or 'linear', merely saying 'it increases'.

Things to Be Careful About

Ensure you are answering for N2O\text{N}_2\text{O} specifically, not the total moles of gas. At 25 C25\text{ }^{\circ}\text{C}, water is liquid, so total gas moles = moles of N2O\text{N}_2\text{O}, but the reasoning must be based on the specific species asked for.

Techniques used
deduce stoichiometric ratio from balanced equationpredict linear relationship
(ii)

Predict quantitatively how the sum of the number of moles of water vapour and nitrogen(I) oxide varies as the number of moles of ammonium nitrate(V) increases, if the products are measured at 110 C110\text{ }^{\circ}\text{C}.

DifficultyMedium-Easy
Worked solution

Answer

The sum of the number of moles of water vapour and nitrogen(I) oxide is directly proportional to the number of moles of ammonium nitrate(V), with a 1:3 ratio.

Final answer

The sum of the number of moles of water vapour and nitrogen(I) oxide is directly proportional to the number of moles of ammonium nitrate(V), with a 1:3 ratio.

Detailed explanation

Background Concept

The physical state of a substance depends on the temperature. Water is a liquid at 25 C25\text{ }^{\circ}\text{C} but a gas (vapour) at 110 C110\text{ }^{\circ}\text{C}. When calculating total moles of gas, all gaseous products must be included.

Understanding the Question

Predict how the total moles of gaseous products (water vapour + nitrogen(I) oxide) vary with the moles of reactant, measured at 110 C110\text{ }^{\circ}\text{C}.

Approach

Determine the state of water at 110 C110\text{ }^{\circ}\text{C}, sum the coefficients of all gaseous products, and establish the ratio with the reactant.

Step-by-Step Reasoning

  1. At 110 C110\text{ }^{\circ}\text{C}, both N2O\text{N}_2\text{O} and H2O\text{H}_2\text{O} are gases.
  2. From the equation: 1 mol NH4NO3\text{NH}_4\text{NO}_3 produces 1 mol N2O\text{N}_2\text{O} and 2 mol H2O\text{H}_2\text{O}.
  3. Total moles of gas produced = 1+2=31 + 2 = 3 moles.
  4. The ratio of total gas moles to reactant moles is 3:1. Thus, the sum of moles of products is directly proportional to the moles of NH4NO3\text{NH}_4\text{NO}_3 with a 1:3 ratio.

Key Takeaways

Always check the physical states at the specified temperature. The total moles of gas can change depending on whether condensation occurs.

Common Mistakes

  • Assuming water is still a liquid at 110 C110\text{ }^{\circ}\text{C} and giving a 1:1 ratio.
  • Forgetting to sum the moles of both gaseous products.

Things to Be Careful About

The question explicitly says 'water vapour', hinting that it is a gas. Ensure the ratio is stated as reactant:products (1:3) or products:reactant (3:1) clearly.

Techniques used
calculate total moles of gaseous productspredict linear relationship at elevated temperature
(iii)

Display both your predictions in the form of sketch graphs on the axes below. Label clearly each axis and each graph line.

3M
DifficultyMedium-Easy
Worked solution

Answer

  • Y-axis: moles of gas (or number of moles)
  • X-axis: moles of NH4NO3\text{NH}_4\text{NO}_3
  • Line 1: N2O\text{N}_2\text{O} at 25 C25\text{ }^{\circ}\text{C} (slope = 1)
  • Line 2: N2O+H2O\text{N}_2\text{O} + \text{H}_2\text{O} at 110 C110\text{ }^{\circ}\text{C} (slope = 3)
Final answer

Two straight lines starting from the origin. Y-axis: moles of gas. X-axis: moles of NH4NO3. Line for 25°C has slope 1, line for 110°C has slope 3.

Detailed explanation

Background Concept

A direct proportionality between two variables is represented by a straight line passing through the origin (0,0) on a graph. The gradient (slope) of this line represents the constant of proportionality (the ratio). Sketch graphs must show correct relative slopes and clear labels, even if exact numerical values are not plotted.

Understanding the Question

Display the predictions from (a)(i) and (a)(ii) as sketch graphs on the provided axes (Fig 1.1). Both axes start at (0,0).

Approach

  1. Define the axes based on the variables being compared (moles of gas vs moles of reactant).
  2. Plot Line 1 for 25 C25\text{ }^{\circ}\text{C}: 1 mol gas per 1 mol reactant (gradient = 1).
  3. Plot Line 2 for 110 C110\text{ }^{\circ}\text{C}: 3 mol gas per 1 mol reactant (gradient = 3).
  4. Label both lines clearly.

Step-by-Step Reasoning

  • The x-axis must be 'moles of NH4NO3\text{NH}_4\text{NO}_3' (independent variable).
  • The y-axis must be 'moles of gas' or 'number of moles' (dependent variable).
  • At 25 C25\text{ }^{\circ}\text{C}, only N2O\text{N}_2\text{O} is gaseous. Ratio is 1:1. Draw a straight line from (0,0) with a moderate slope. Label it 'N2O\text{N}_2\text{O} at 25 C25\text{ }^{\circ}\text{C}' or 'gas at 25 C25\text{ }^{\circ}\text{C}'.
  • At 110 C110\text{ }^{\circ}\text{C}, both N2O\text{N}_2\text{O} and H2O\text{H}_2\text{O} are gaseous. Total ratio is 3:1. Draw a straight line from (0,0) with a steeper slope (exactly 3 times steeper). Label it 'N2O+H2O\text{N}_2\text{O} + \text{H}_2\text{O} at 110 C110\text{ }^{\circ}\text{C}' or 'total gas at 110 C110\text{ }^{\circ}\text{C}'.
  • Ensure neither line is curved or has a plateau; the decomposition is complete and stoichiometric.

Key Takeaways

Sketch graphs test your understanding of relationships. Correct labels and relative slopes are more important than exact data points.

Common Mistakes

  • Drawing curves instead of straight lines.
  • Forgetting to label the lines with the temperature or gas identity.
  • Making the axes start at non-zero values (they must start at 0,0 as shown in Fig 1.1).

Things to Be Careful About

The mark scheme specifically looks for 'no curves or plateaus'. Both reactions are 100% complete decompositions, so the lines must continue linearly. The higher temperature line MUST have the greater slope.

Techniques used
sketch linear graphs from origindistinguish slopes for different temperatures
(b)

In the experiment you are about to plan to test your prediction in (a)(i) at 25 C25\text{ }^{\circ}\text{C}, identify the following.

2M
(i)

the independent variable

DifficultyEasy
Worked solution

Answer

The mass (or number of moles) of ammonium nitrate(V).

Final answer

mass (or moles) of ammonium nitrate(V)

Detailed explanation

Background Concept

In an experiment, the independent variable is the factor that the experimenter deliberately changes or controls to observe its effect on another variable.

Understanding the Question

Identify the independent variable for the experiment planned in part (d), which tests how the amount of product changes as the mass of ammonium nitrate(V) changes.

Approach

The question stem states: 'confirm that it remains unchanged as the mass of ammonium nitrate(V) changes'. Therefore, the mass (or moles) of ammonium nitrate is the variable being changed.

Step-by-Step Reasoning

  • The experiment varies the amount of reactant to see the effect on the product.
  • The independent variable is the mass or number of moles of ammonium nitrate(V) heated.

Key Takeaways

The independent variable is what you change; the dependent variable is what you measure.

Common Mistakes

  • Confusing independent and dependent variables.
  • Stating 'temperature' as the independent variable (temperature is kept constant at 25 C25\text{ }^{\circ}\text{C} for the gas measurement).

Things to Be Careful About

'Moles' or 'mass' are both acceptable. Do not just say 'ammonium nitrate'; specify the quantity (mass/moles).

Techniques used
identify independent variable
(ii)

the dependent variable

DifficultyEasy
Worked solution

Answer

The volume (or number of moles) of nitrogen(I) oxide collected.

Final answer

volume (or moles) of nitrogen(I) oxide

Detailed explanation

Background Concept

The dependent variable is the factor that is measured or observed in response to changes in the independent variable.

Understanding the Question

Identify the dependent variable for the experiment at 25 C25\text{ }^{\circ}\text{C}.

Approach

The experiment measures the amount of nitrogen(I) oxide produced from different amounts of ammonium nitrate. In practice, this is measured as the volume of gas collected.

Step-by-Step Reasoning

  • The goal is to investigate the molar ratio.
  • You measure the volume of N2O\text{N}_2\text{O} gas collected using a gas syringe or burette.
  • This volume (which can be converted to moles) is the dependent variable.

Key Takeaways

The dependent variable is what you measure to test your hypothesis.

Common Mistakes

  • Stating 'mass of ammonium nitrate' (this is the independent variable).
  • Stating 'temperature' (this is a control variable).

Things to Be Careful About

'Volume' is the practical measurement; 'moles' is the calculated value. Both are acceptable as the dependent variable in this context.

Techniques used
identify dependent variable
(c)

Draw a diagram of the apparatus and the experimental set up you would use to carry out this experiment. Your apparatus should use only standard items found in a school or college laboratory and show clearly

(i) how the solid will be heated,
(ii) how the water vapour will be condensed into a liquid and collected. Ice is available,
(iii) how the nitrogen(I) oxide will be collected.

Label each piece of apparatus used, indicating its size or capacity.

3M
DifficultyMedium
Worked solution

Answer

Apparatus required:

  • Hard glass boiling tube (or test tube) with rubber bung and delivery tube.
  • Bunsen burner (or test tube holder in flame).
  • U-tube or test tube in a beaker of crushed ice.
  • Gas syringe (minimum 10 cm310\text{ cm}^3, labelled with capacity) or measuring cylinder.
Final answer

See diagram description: heated boiling tube with bung, connected to ice-cooled U-tube for water condensation, connected to a calibrated gas syringe (min 10 cm3) for N2O collection.

Detailed explanation

Background Concept

When decomposing a solid that produces both a condensable vapour and a permanent gas, the apparatus must: (1) safely heat the solid, (2) condense and collect the vapour to prevent it from interfering with gas volume measurement, and (3) accurately measure the volume of the permanent gas.

Understanding the Question

Draw a labelled diagram showing how to heat the solid, condense the water vapour using ice, and collect the nitrogen(I) oxide gas. Use standard school laboratory equipment.

Approach

  1. Heating: Use a hard glass boiling tube containing the solid, clamped and heated by a Bunsen burner. Seal with a rubber bung and delivery tube. (No water baths or hot plates as per mark scheme).
  2. Condensation: Route the delivery tube into a U-tube or test tube immersed in crushed ice. This cools the water vapour to liquid, which is collected here.
  3. Gas Collection: Route the remaining gas (now only N2O\text{N}_2\text{O}) into a calibrated gas collecting device. A gas syringe is ideal. It must be labelled with its capacity (e.g., '50 cm350\text{ cm}^3 gas syringe').

Step-by-Step Reasoning

  • Heating apparatus: A hard glass boiling tube is essential as it can withstand direct flame heating without cracking. It must be closed (bunged) with a delivery tube to direct the products. Label: 'hard glass boiling tube', 'Bunsen burner'.
  • Water condenser: The delivery tube from the boiling tube leads into a U-tube or a test tube placed in a beaker containing crushed ice. The ice cools the water vapour to liquid water (25 C25\text{ }^{\circ}\text{C}), which condenses and is trapped. Label: 'U-tube / test tube', 'crushed ice', 'beaker'. The connection to the gas collector must be gas-tight.
  • Gas collector: A delivery tube from the ice-cooled condenser leads into a gas syringe. The syringe must be calibrated and labelled with its size (minimum 10 cm310\text{ cm}^3, e.g., '50 cm350\text{ cm}^3 gas syringe'). Alternatively, an inverted burette or measuring cylinder could be used, but a syringe is cleaner and avoids water vapour issues if the condenser is effective.

Key Takeaways

Apparatus diagrams for multi-product decomposition must clearly show the sequence: reaction -> condensation -> gas collection. All key components must be labelled with names and sizes.

Common Mistakes

  • Using a water bath or hot plate to heat the solid (mark scheme explicitly rejects this).
  • Forgetting to label the gas collector with its capacity (e.g., just writing 'gas syringe' without '50 cm350\text{ cm}^3').
  • Not making the connection between the condenser and gas collector gas-tight (if gas collection is attempted).
  • Drawing a Liebig condenser without ensuring it is connected correctly and gas-tight to the collector.

Things to Be Careful About

The mark scheme requires 'minimum 10 cm310\text{ cm}^3' for the gas collector. A 10 cm310\text{ cm}^3 syringe is too small for practical experiments with multiple data points; a 50 cm350\text{ cm}^3 or 100 cm3100\text{ cm}^3 syringe is more realistic. Ensure the ice is explicitly mentioned as the cooling agent for the water condenser.

Techniques used
design apparatus for solid decompositionincorporate condensation and gas collection
(d)

Using the apparatus shown in (c) design a laboratory experiment to test your prediction in (a)(i) for an experiment at 25 C25\text{ }^{\circ}\text{C}.

In addition to the standard apparatus present in a laboratory you are provided with the following materials.

  • a sample of solid ammonium nitrate(V)
  • crushed ice

Give a step-by-step description of how you would carry out the experiment,

(i) to produce enough results to give sufficient data to plot a graph as in (a)(iii),
(ii) by stating the volumes of nitrogen(I) oxide you would collect,
(iii) by calculating the mass of ammonium nitrate(V) needed to produce one of the volumes of nitrogen(I) oxide suggested in (ii),
(iv) by stating how you would ensure that decomposition was complete.

[ArA_r: H, 1.0; N, 14.0; O, 16.0; the molar volume of a gas at 25 C25\text{ }^{\circ}\text{C}, 24.0 dm324.0\text{ dm}^3]

4M
DifficultyMedium-Hard
Worked solution

Answer

(i) Procedure for sufficient data:
Perform at least five separate experiments. For each experiment, heat a different, pre-measured mass of solid ammonium nitrate(V) and record the maximum volume of nitrogen(I) oxide gas collected in the gas syringe.

(ii) Intended gas volumes:
Collect volumes ranging from 10 cm310\text{ cm}^3 to 30 cm330\text{ cm}^3 (e.g., 10,15,20,25,30 cm310, 15, 20, 25, 30\text{ cm}^3). The maximum volume must not exceed the capacity of the gas syringe (e.g., 50 cm350\text{ cm}^3).

(iii) Calculation for mass of NH4NO3\text{NH}_4\text{NO}_3:
To produce 30 cm330\text{ cm}^3 (0.030 dm30.030\text{ dm}^3) of N2O\text{N}_2\text{O} at 25 C25\text{ }^{\circ}\text{C}:

moles of N2O=0.03024.0=0.00125 mol\text{moles of N}_2\text{O} = \frac{0.030}{24.0} = 0.00125\text{ mol}

From the 1:1 ratio, moles of NH4NO3=0.00125 mol\text{NH}_4\text{NO}_3 = 0.00125\text{ mol}.

Mr(NH4NO3)=14.0+4(1.0)+14.0+3(16.0)=80.0M_r(\text{NH}_4\text{NO}_3) = 14.0 + 4(1.0) + 14.0 + 3(16.0) = 80.0 mass=0.00125×80.0=0.100 g\text{mass} = 0.00125 \times 80.0 = 0.100\text{ g}

(Use a similar calculation for other target volumes, adjusting the mass accordingly).

(iv) Ensuring complete decomposition:
Continue heating until the volume of gas in the syringe no longer increases (constant volume), or until all the solid white ammonium nitrate has disappeared from the boiling tube.

Final answer

See working: 5 experiments, volumes 10-30 cm3, mass calculation (e.g., 0.100 g for 30 cm3), stop when gas volume is constant or solid disappears.

Detailed explanation

Background Concept

To establish a linear relationship experimentally, you need multiple data points (at least 5) covering a reasonable range of the independent variable. You must be able to predict the expected outcomes (volumes) and calculate the required starting materials (masses) to achieve those outcomes. The experiment must have a clear, observable end-point to ensure the reaction is complete before recording data.

Understanding the Question

Design the experiment to test the prediction in (a)(i). This involves: (i) planning enough data points for a graph, (ii) stating target gas volumes, (iii) calculating the mass of reactant needed for one target volume, and (iv) defining how you know the reaction is finished.

Approach

  1. Data points: Plan 5+ experiments with varying masses of NH4NO3\text{NH}_4\text{NO}_3.
  2. Volumes: Choose a range of gas volumes that fit within the gas syringe (e.g., 1030 cm310-30\text{ cm}^3 in a 50 cm350\text{ cm}^3 syringe).
  3. Calculation: Use the molar volume (24.0 dm3 mol124.0\text{ dm}^3\text{ mol}^{-1} at 25 C25\text{ }^{\circ}\text{C}) and stoichiometry to find the mass of NH4NO3\text{NH}_4\text{NO}_3 needed for one of the target volumes.
  4. End-point: Define an observable sign that decomposition is complete (constant gas volume or solid gone).

Step-by-Step Reasoning

(i) Sufficient data:
To plot a meaningful graph as in (a)(iii), you need at least 5 data points. This means performing the experiment 5 times with 5 different masses of NH4NO3\text{NH}_4\text{NO}_3. Record the volume of gas for each.

(ii) Intended gas volumes:
Assume a 50 cm350\text{ cm}^3 gas syringe. A good range is 10 cm310\text{ cm}^3 to 30 cm330\text{ cm}^3. The minimum should be 10 cm3\ge 10\text{ cm}^3 to reduce percentage reading errors. The maximum should be 30 cm3\le 30\text{ cm}^3 to leave room in the syringe and avoid exceeding its capacity. State these volumes explicitly.

(iii) Calculation:
Let's calculate the mass needed to produce 30 cm330\text{ cm}^3 (0.030 dm30.030\text{ dm}^3) of N2O\text{N}_2\text{O}.

  • Moles of N2O=volume in dm3molar volume=0.03024.0=0.00125 mol\text{N}_2\text{O} = \frac{\text{volume in dm}^3}{\text{molar volume}} = \frac{0.030}{24.0} = 0.00125\text{ mol}.
  • From the equation NH4NO3N2O+2H2O\text{NH}_4\text{NO}_3 \rightarrow \text{N}_2\text{O} + 2\text{H}_2\text{O}, the ratio is 1:1. So, moles of NH4NO3=0.00125 mol\text{NH}_4\text{NO}_3 = 0.00125\text{ mol}.
  • Mr(NH4NO3)=14.0+4.0+14.0+48.0=80.0 g mol1M_r(\text{NH}_4\text{NO}_3) = 14.0 + 4.0 + 14.0 + 48.0 = 80.0\text{ g mol}^{-1}.
  • Mass = moles ×Mr=0.00125×80.0=0.100 g\times M_r = 0.00125 \times 80.0 = 0.100\text{ g}.
    Show this working clearly. The mark scheme allows a volume from a stated mass, but calculating mass from volume is the standard approach.

(iv) Ensuring complete decomposition:
The mark scheme specifically requires an observation, not a deduction. You cannot just say 'wait until it's all decomposed'. You must say: 'heat until the volume reading on the gas syringe stops increasing (becomes constant)' OR 'heat until all the solid white powder has disappeared'.

Key Takeaways

Experimental design requires planning the range of data, calculating required quantities, and defining clear observable end-points.

Common Mistakes

  • Planning only 2 or 3 experiments (need at least 5 for a reliable graph).
  • Stating volumes outside the range (e.g., 5 cm35\text{ cm}^3 is too small for accurate reading; 40 cm340\text{ cm}^3 might exceed a small syringe).
  • Calculating mass without showing the mole conversion from volume.
  • Stating 'wait until no more gas is produced' as the end-point (this is a deduction/assumption, not an observation. The observation is 'the syringe plunger stops moving' or 'the volume reading is constant').

Things to Be Careful About

  • Significant figures: The molar volume is given as 24.024.0 (3 s.f.), so your mass should be to 3 s.f. (0.100 g0.100\text{ g}, not 0.1 g0.1\text{ g}).
  • Units: Convert cm3\text{cm}^3 to dm3\text{dm}^3 when using the molar volume (24.0 dm3 mol124.0\text{ dm}^3\text{ mol}^{-1}). 30 cm3=0.030 dm330\text{ cm}^3 = 0.030\text{ dm}^3.
  • The calculation is not restricted to the maximum capacity of the collector; you can calculate for any volume in your planned range.
Techniques used
plan repeated experiments for graph plottingcalculate reactant mass from gas volumedetermine end-point of reaction
(e)

State one hazard that must be considered when planning the experiment and describe a precaution that should be taken to minimise the risk from this hazard.

1M
DifficultyMedium-Easy
Worked solution

Answer

Hazard: Ammonium nitrate(V) is an oxidising agent and can be explosive when mixed with combustible material (or organic matter).
Precaution: Ensure the salt is not contaminated with organic matter / keep away from combustible materials. Wear chemical-resistant gloves (or use tongs to handle hot apparatus).

Final answer

Hazard: oxidising/explosive with combustibles. Precaution: keep away from combustible material / wear resistant gloves.

Detailed explanation

Background Concept

Ammonium nitrate is a well-known oxidising agent used in fertilisers and explosives. When heated, it can decompose rapidly. The key hazard is its reactivity with combustible (organic) materials, which can lead to fire or explosion. Additionally, the apparatus becomes very hot during the experiment.

Understanding the Question

Identify one hazard from the provided information and state a practical precaution to minimise the risk.

Approach

Read the 'hazcard' information in the question stem. Extract the hazard (oxidising, explosive with organics) and match it with a standard laboratory safety procedure.

Step-by-Step Reasoning

  • Hazard: The text states 'Oxidising: Contact with combustible material may cause fire. Explosive when mixed with combustible material. Do not allow the salt to become contaminated with organic matter'.
  • Precaution 1 (Chemical hazard): Keep the ammonium nitrate away from any combustible materials (e.g., paper, wood, solvents). Do not grind it (as grinding can generate heat/sparks). Wear chemical-resistant gloves to prevent skin contact and contamination.
  • Precaution 2 (Thermal hazard): The boiling tube will be very hot. Use heat-resistant gloves or tongs to handle the apparatus after heating.

Key Takeaways

Always read the provided hazard information. Match the specific hazard (oxidising, corrosive, flammable) with the correct PPE or handling procedure.

Common Mistakes

  • Stating 'ammonium nitrate is flammable' (it is an oxidiser, not combustible itself).
  • Giving a vague precaution like 'be careful' or 'use safety goggles' (must be specific to the hazard identified).
  • Not linking the precaution to the hazard (e.g., saying 'wear gloves' without specifying chemical-resistant, or not mentioning keeping away from combustibles).

Things to Be Careful About

The mark scheme accepts 'hot apparatus' as a hazard with 'heat resistant gloves/tongs' as the precaution. However, the primary hazard highlighted in the text is the oxidising/explosive nature. Addressing the chemical hazard is safer.

Techniques used
identify hazards from provided informationpropose risk management precautions
(f)

Draw a table with appropriate headings to show the data you would record when carrying out your experiments and the values you would calculate in order to construct a graph to support or reject your prediction in (a)(i). The headings should include the appropriate units.

2M
DifficultyMedium-Easy
Worked solution

Answer

Mass of NH4NO3\text{NH}_4\text{NO}_3 / gVolume of N2O\text{N}_2\text{O} / cm3\text{cm}^3Number of moles of NH4NO3\text{NH}_4\text{NO}_3Number of moles of N2O\text{N}_2\text{O}
0.0506.00.0006250.000625
0.10012.00.001250.00125
0.15018.00.001880.00188
0.20024.00.002500.00250
0.25030.00.003130.00313

(Note: The last two columns have no units. The volume can be in dm3\text{dm}^3 instead of cm3\text{cm}^3.)

Final answer

Table with 4 columns: Mass of NH4NO3 (g), Volume of N2O (cm3), Moles of NH4NO3 (no unit), Moles of N2O (no unit).

Detailed explanation

Background Concept

A data table for plotting a graph must include the raw measurements (with units) and the calculated values needed for the axes (without units, as axes are typically labelled with the quantity, e.g., 'moles'). The table should have clear headings with quantities and units.

Understanding the Question

Draw a table showing the data to be recorded and the values to be calculated to plot the graph from (a)(iii) (moles of gas vs moles of reactant).

Approach

  1. Raw data columns: Mass of NH4NO3\text{NH}_4\text{NO}_3 (measured) and Volume of N2O\text{N}_2\text{O} (measured). Both need units.
  2. Calculated columns: Moles of NH4NO3\text{NH}_4\text{NO}_3 (from mass) and Moles of N2O\text{N}_2\text{O} (from volume). These are dimensionless numbers (no units in the column heading).
  3. Format: Use a standard table with 4 columns and at least 5 rows of data (or placeholders).

Step-by-Step Reasoning

  • Column 1: 'Mass of NH4NO3\text{NH}_4\text{NO}_3 / g' or 'Mass of ammonium nitrate (g)'. This is the independent variable.
  • Column 2: 'Volume of N2O\text{N}_2\text{O} / cm3\text{cm}^3' or 'Volume of nitrogen(I) oxide (dm3\text{dm}^3)'. This is the raw dependent variable.
  • Column 3: 'Number of moles of NH4NO3\text{NH}_4\text{NO}_3' (no unit). Calculated as mass / 80.0.
  • Column 4: 'Number of moles of N2O\text{N}_2\text{O}' (no unit). Calculated as volume (in dm3\text{dm}^3) / 24.0.
  • The graph will plot Column 4 (y-axis) against Column 3 (x-axis).
  • Ensure the table has at least 5 rows to show sufficient data points.

Key Takeaways

Data tables must clearly separate raw measurements (with units) from calculated values (without units in the heading). The columns must directly correspond to the axes of the final graph.

Common Mistakes

  • Including units in the calculated mole columns (e.g., 'moles / mol'). The heading should just be 'Number of moles'.
  • Forgetting units in the raw data columns (e.g., 'Mass of NH4NO3' without '/ g').
  • Using 'Amount of NH4NO3' instead of 'Mass' (amount is ambiguous; mass or moles is required, but mass is the raw measurement).

Things to Be Careful About

The mark scheme requires exactly four fully correct columns for 2 marks. Three correct columns give 1 mark. Ensure all four are present and correctly formatted. The unit for volume can be cm3\text{cm}^3 or dm3\text{dm}^3, but if cm3\text{cm}^3 is used, the calculation to moles must convert to dm3\text{dm}^3 first (or use 24000 cm3 mol124000\text{ cm}^3\text{ mol}^{-1}).

Techniques used
design data table for graph plottinginclude correct units and calculated columns

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