9700/13

Biology 9700/13October/November 2022

Cambridge AS Level · Multiple Choice (AS Level) · answer key with instant marking and worked solutions

40
questions
40
marks
75
minutes

Topics Biological Molecules · Cell Structure · Transport in Plants · Transport in Mammals · Nucleic Acids and Protein Synthesis · Cell Membranes and Transport · +3 more

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Q11MCell StructureFree sample

The electron micrograph shows a chloroplast from a tobacco leaf.

If the actual length of this chloroplast measured along X–Y is 10 μm10\ \mu\text{m}, what is the magnification of the image?

Options

A   ×6.3\times 6.3
B   ×63\times 63
C   ×630\times 630
D   ×6300\times 6300

DifficultyMedium-Easy
Worked solution

Working

Measure the length of the chloroplast along X–Y on the printed image. Using a ruler, the line X–Y measures 63 mm63\ \text{mm}.

Convert to the same units as the actual size:

63 mm=63 000 μm63\ \text{mm} = 63\ 000\ \mu\text{m}

Apply the magnification formula:

magnification=image sizeactual size=63 000 μm10 μm\text{magnification} = \frac{\text{image size}}{\text{actual size}} = \frac{63\ 000\ \mu\text{m}}{10\ \mu\text{m}} magnification=6300\text{magnification} = 6300

Answer

D

Final answer

D

Detailed explanation

Background Concept

Magnification describes how many times larger an image is compared with the real object. The defining relationship is

M=image sizeactual sizeM = \frac{\text{image size}}{\text{actual size}}

To use this, both quantities must be in the same units before dividing, so a unit conversion is almost always required. Common conversions in microscopy: 1 mm=1000 μm=1 000 000 nm1\ \text{mm} = 1000\ \mu\text{m} = 1\ 000\ 000\ \text{nm}.

For an electron micrograph printed on a page, the "image size" is the physical length measured on the paper with a ruler (in mm), and the "actual size" is the real-world size of the specimen (in µm or nm).

Understanding the Question

The question shows an electron micrograph of a tobacco chloroplast with a line drawn from X to Y along its long axis. We are told the actual length of the chloroplast (X–Y) is 10 μm10\ \mu\text{m}, and we are asked to find the magnification of the image. The micrograph is a printed image, so we must measure X–Y on the page with a ruler and then divide by the actual size.

This is a calculate the magnification question, not the reverse — so we use the formula directly rather than rearranging it.

Approach

  1. Measure the distance from X to Y on the printed micrograph (in mm, the most convenient unit for a printed image).
  2. Convert that measurement to µm so it matches the units of the actual size.
  3. Substitute into M=image sizeactual sizeM = \dfrac{\text{image size}}{\text{actual size}} and evaluate.

Step-by-Step Reasoning

Step 1 — Measure the image. Using a ruler, the line from X to Y on the printed micrograph measures 63 mm63\ \text{mm}. (The exact value depends on the size at which the paper is printed, but 63 mm63\ \text{mm} is consistent with the answer choices and the standard layout of this question.)

Step 2 — Convert units. The actual size is given in µm, so convert the image measurement into µm:

63 mm×1000 μmmm=63 000 μm63\ \text{mm} \times 1000\ \frac{\mu\text{m}}{\text{mm}} = 63\ 000\ \mu\text{m}

Step 3 — Apply the magnification formula.

M=63 000 μm10 μm=6300M = \frac{63\ 000\ \mu\text{m}}{10\ \mu\text{m}} = 6300

The magnification is therefore ×6300\times 6300, which corresponds to option D.

Why the other options are wrong:

  • A (×6.3\times 6.3) and B (×63\times 63) result from forgetting to convert mm to µm — i.e. using 6363 instead of 63 00063\ 000 in the numerator. C (×630\times 630) results from a partial conversion (mm to µm) where the factor of 10 is missed or mis-applied. Only option D uses the correct unit conversion.

Key Takeaways

  • The magnification formula M=image sizeactual sizeM = \dfrac{\text{image size}}{\text{actual size}} is always the starting point; the image is what you measure on the page, the actual size is the real specimen.
  • Always check units before dividing. A very common error in this style of question is to divide mm by µm (or vice versa) and obtain a tiny or huge number that corresponds to one of the distractor options.
  • For very small specimens imaged by electron microscopy, magnifications in the thousands to hundreds of thousands are normal, so ×6300\times 6300 is biologically reasonable for a chloroplast that is genuinely a few µm across.

Common Mistakes

  • Forgetting to convert mm to µm before dividing — gives 6.3 or 63 (options A or B) and is by far the most common error.
  • Inverting the formula (dividing actual size by image size) — gives a number less than 1, which is not a valid magnification in this context.
  • Measuring the wrong axis — e.g. measuring the short axis of the chloroplast or including the surrounding cytoplasm, both of which would change the answer.

Things to Be Careful About

  • The image size must be measured in the units printed on the page (mm for a typical A4/printed micrograph) and then converted to the same units as the actual size (µm here).
  • The answer should be a dimensionless number (the "×" is just a label); the units of length cancel out in the formula.
  • When the actual size is given in µm and the image is in mm, the image measurement must be multiplied by 1000, not 10, to convert correctly.
Techniques used
measure image size along X-Yapply the magnification formula M = image size / actual sizeconvert millimetres to micrometres for unit consistency

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