9700/33

Biology 9700/33May/June 2020

Cambridge AS Level · Advanced Practical Skills · worked solutions for every part, with the mark scheme

2
questions
40
marks
120
minutes

Topics Manipulation, Measurement and Observation · Presentation of Data and Observations · Analysis, Conclusions and Evaluation · Use of the Light Microscope

Q1Manipulation, Measurement and ObservationPresentation of Data and ObservationsAnalysis, Conclusions and EvaluationFree sample

Energy drinks contain a high concentration of carbohydrates, such as glucose, as a source of energy.

Glucose is a monosaccharide which can be quickly metabolised by body cells, releasing energy during exercise.

Glucose changes the colour of potassium manganate(VII) solution, P, from purple to colourless. The end-point is when P is completely colourless.

You will need to:
• prepare different concentrations of glucose solution
• record the time taken to reach the end-point for the known glucose concentrations
• use your results to estimate the concentration of glucose in an energy drink, U.

You are provided with the materials shown in Table 1.1.

Table 1.1

labelledcontentsriskvolume/cm3\text{cm}^3
G20% glucose solutionnone50
Wdistilled waternone20
Adilute sulfuric acidirritant20
Ppotassium manganate(VII) solutionlow risk irritant20
Uenergy drinknone10

It is recommended that you wear suitable eye protection.

If A or P come into contact with your skin, wash off immediately under cold water.

(a)

You will need to prepare different concentrations of glucose solution.

The lowest concentration you will prepare is 12%.

You will need to prepare 10cm310\,\text{cm}^3 of each concentration, using G and W.

Table 1.2 shows how to make up two of the concentrations of glucose solution you will use.

Decide which other concentrations of glucose solution you will use.

(i)

Complete Table 1.2 to show how you will prepare the concentrations of glucose you will use.

Table 1.2

percentage concentration of glucosevolume of G/cm3\text{cm}^3volume of W/cm3\text{cm}^3
20100
1264
2M
DifficultyMedium-Easy
Worked solution

Answer

percentage concentration of glucosevolume of G / cm3\text{cm}^3volume of W / cm3\text{cm}^3
20100
1891
1682
1473
1264
Final answer

20, 18, 16, 14, 12% with G volumes 10, 9, 8, 7, 6 cm³ and W volumes 0, 1, 2, 3, 4 cm³

Detailed explanation

Background Concept

A serial dilution is a stepwise reduction in the concentration of a stock solution, made by adding a fixed volume of the stock to a fixed volume of diluent (here distilled water, W). Because every dilution has the same final volume (10 cm³), the volume of the 20% stock (G) needed to make a target concentration CC is:

VG=C20×10 cm3=C2 cm3V_G = \frac{C}{20} \times 10\ \text{cm}^3 = \frac{C}{2}\ \text{cm}^3

and the diluent volume is VW=10VGV_W = 10 - V_G.

Understanding the Question

You are told to prepare 10 cm³ of each glucose concentration using G (20% stock) and W (distilled water), with 12% as the lowest concentration. The 20% and 12% rows are already filled in. You must decide which intermediate concentrations to use and complete the G and W volumes for each row.

Approach

Choose at least three intermediate concentrations between 20% and 12% at a regular interval, then use the dilution formula to find the volume of G required for each. The simplest interval is 2% (20, 18, 16, 14, 12). Five evenly spaced rows will make any later graph smooth and any interpolation between standards more accurate.

Step-by-Step Reasoning

  • 20%: VG=20/2=10 cm3V_G = 20/2 = 10\ \text{cm}^3, VW=0 cm3V_W = 0\ \text{cm}^3 (already in the table).
  • 18%: VG=18/2=9 cm3V_G = 18/2 = 9\ \text{cm}^3, VW=109=1 cm3V_W = 10 - 9 = 1\ \text{cm}^3.
  • 16%: VG=16/2=8 cm3V_G = 16/2 = 8\ \text{cm}^3, VW=108=2 cm3V_W = 10 - 8 = 2\ \text{cm}^3.
  • 14%: VG=14/2=7 cm3V_G = 14/2 = 7\ \text{cm}^3, VW=107=3 cm3V_W = 10 - 7 = 3\ \text{cm}^3.
  • 12%: VG=12/2=6 cm3V_G = 12/2 = 6\ \text{cm}^3, VW=106=4 cm3V_W = 10 - 6 = 4\ \text{cm}^3 (already in the table).

Each row sums to 10 cm³, satisfying the requirement.

Key Takeaways

  • A dilution of a stock of concentration C0C_0 to a target CC in a fixed final volume VV needs VG=(C/C0)×VV_G = (C/C_0) \times V of stock and VVGV - V_G of diluent.
  • Choosing regular intervals between concentrations (e.g. every 2%) gives a smoother calibration curve and easier interpolation later.

Common Mistakes

  • Choosing a non-integer number of cm³ (e.g. trying to make 13% would give 6.5 cm³ of G, which is hard to measure accurately with a 10 cm³ measuring cylinder).
  • Forgetting that the volumes of G and W must add up to 10 cm³.
  • Listing concentrations that don't change regularly from 20% down to 12%.

Things to Be Careful About

  • The mark scheme requires at least three concentrations between 20% and 12%; four or five is fine and usually safer.
  • Leave the two given rows (20% and 12%) exactly as they appear - only the intermediate rows are completed.
Techniques used
calculate volumes for a serial dilutioncomplete a table of concentrations and diluent volumes
(ii)

Carry out step 1 to step 8.

  1. Prepare the concentrations of glucose solution, as shown in Table 1.2, in the beakers provided.
  2. Label test-tubes with the concentrations of glucose prepared in step 1.
  3. Put 1cm31\,\text{cm}^3 of 20% glucose solution into the appropriately labelled test-tube.
  4. Repeat step 3 with each of the other concentrations of glucose.
  5. Put 1cm31\,\text{cm}^3 of A into each of the test-tubes. Shake gently to mix.

The reaction will start as soon as you put P into the test-tubes (step 6).

Do not stop the timer – keep it running continuously.

  1. Put 1cm31\,\text{cm}^3 of P into each of the test-tubes and start timing. Shake gently to mix.
  2. Measure the time taken for each test-tube to reach the end-point. As each end-point is reached, record the time taken in the space provided for raw results. Do not stop the timer.
  3. Record in (a)(ii) the time taken for each test-tube to reach the end-point.

If the end-point has not been reached after 600 seconds (10 minutes) record the time as 'more than 600'.

Record your results in an appropriate table.

5M
DifficultyMedium-Easy
Worked solution

Answer

percentage concentration of glucosetime / s\text{s}
2032
1845
1660
1490
12150

(Times shown are a representative example; the actual student data will vary but must show the trend: the highest concentration of glucose gives the shortest time to the end-point.)

Final answer

See working; representative times show the expected trend (20% ≈ 32 s, decreasing to 12% ≈ 150 s).

Detailed explanation

Background Concept

In Paper 3, a results table is the formal record of raw data. It must show:

  • the independent variable (what you deliberately changed) in the left-hand column;
  • the dependent variable (what you measured) in the right-hand column, with its unit in the heading;
  • one row per experimental condition;
  • a clear trend or pattern that matches the prediction.

In this experiment the independent variable is the percentage concentration of glucose and the dependent variable is the time taken for potassium manganate(VII) (P) to be decolourised from purple to colourless. Because higher concentrations of glucose provide more reducing sugar, they decolourise the permanganate faster, so the time decreases as the concentration rises.

Understanding the Question

You carry out the procedure for each of the five concentrations in Table 1.2, starting all the reactions at the same moment and recording the time at which each test-tube becomes completely colourless. You then write these times in a results table.

Approach

Before you start, decide the layout of your results table - it should be ready before you mix any reagents because the timer is running continuously. Use a left-hand column for the independent variable and a right-hand column for the dependent variable (with units in the heading). Record each time as a whole second (the mark scheme will not accept decimals here).

Step-by-Step Reasoning

  • The independent variable is the percentage concentration of glucose, so this heading goes in the left column.
  • The dependent variable is the time taken for the end-point, so this heading goes in the right column. The unit is seconds, so write 'time / s' (or 'time / seconds').
  • As each tube becomes colourless, glance at the timer and record the whole-second reading in the corresponding row.
  • Because higher concentrations react faster, the 20% tube should clear first, the 18% tube next, and so on down to 12% last. The expected trend is therefore monotonically decreasing time with increasing concentration.
  • A representative set of times (illustrative only) might be: 20% = 32 s, 18% = 45 s, 16% = 60 s, 14% = 90 s, 12% = 150 s. The exact values will differ for every student but the order must be the same.

Key Takeaways

  • Always pre-draw the results table before the timed run so you can record immediately.
  • The independent variable is on the left, the dependent variable on the right, and the unit is part of the dependent-variable heading.
  • Record times as whole seconds; the mark scheme will not credit decimal places here.

Common Mistakes

  • Putting the headings in the wrong order (independent variable on the right).
  • Forgetting the unit in the dependent-variable heading.
  • Recording decimal seconds (e.g. 32.4 s) - the mark scheme requires whole seconds.
  • Recording fewer than four concentrations when five were prepared.
  • Misreading the timer because the reactions are started simultaneously and the eye is drawn to the first tube to clear.

Things to Be Careful About

  • The timer is NOT to be stopped between tubes; each end-point is recorded as the elapsed time on a continuously running clock.
  • If a tube has not cleared by 600 s, record 'more than 600' rather than leaving the cell blank.
  • The order in which tubes clear must match the order of decreasing concentration - if not, the data are likely to be wrong and should be repeated.
Techniques used
record experimental results in a table with appropriate headings and unitsrecognise the expected trend in the data
(iii)
  1. Label a test-tube U and put 1cm31\,\text{cm}^3 of U into this test-tube.
  2. Repeat step 5 to step 7 using the test-tube labelled U.

Record the time taken to reach the end-point for U.

time for U = ______ s\text{s}

1M
DifficultyEasy
Worked solution

Answer

time for U = 35 s\text{s} (representative; the recorded time should be closest to the 20% standard)

Final answer

35 s (representative; the actual value depends on the student's own data but should be closest to the 20% standard)

Detailed explanation

Background Concept

The unknown energy drink U contains glucose (and possibly other reducing sugars). The same decolourisation reaction with potassium manganate(VII) will therefore take a time that depends on the glucose concentration. By comparing the time for U with the times for the standards, the concentration of glucose in U can be estimated.

Understanding the Question

You have just run a new test-tube containing 1 cm³ of U instead of a standard glucose solution. The timer has been running continuously since the standards were started. You read the time at which the U tube becomes completely colourless and record it.

Approach

Carry out steps 5-7 of the procedure on the U tube exactly as for the standards. As the purple colour disappears, read the timer to the nearest whole second and write this in the answer line.

Step-by-Step Reasoning

  • Add 1 cm³ of A (dilute sulfuric acid) to the U tube and shake.
  • Add 1 cm³ of P (potassium manganate(VII)) and start observing.
  • When the purple colour has completely disappeared, glance at the continuously running timer and read the time to the nearest whole second.
  • Record this time. The mark scheme requires the time for U to be closest to that of the 20% standard, so for representative data where the 20% standard took 32 s, U might give a reading of about 35 s.

Key Takeaways

  • The same procedural steps and timing precision must be applied to the unknown as to the standards, otherwise the comparison is invalid.
  • The time for U will be read against the same continuously running timer that was used for the standards.

Common Mistakes

  • Stopping and restarting the timer for U (the timer must keep running).
  • Using a different volume of U from that of the standards (must be 1 cm³).
  • Recording a time that is wildly different from the 20% standard, which would suggest either a procedural slip or that U is much more or much less concentrated than expected.

Things to Be Careful About

  • The mark scheme only credits the reading if it is close to the 20% standard - if it is not, the procedure has probably been done incorrectly and should be repeated before (a)(iv) is attempted.
Techniques used
read a continuously running timer to the nearest whole secondrecord a single measurement in an answer line
(iv)

Estimate the percentage concentration of glucose in U.

concentration in U = ______ %\%

1M
DifficultyMedium-Easy
Worked solution

Answer

concentration in U ≈ 19% (representative; the time for U from (a)(iii) is read against the standards from (a)(ii) and interpolated between the two closest standards, here 20% and 18%)

Final answer

≈ 19% (representative; actual value depends on the student's data)

Detailed explanation

Background Concept

The reaction time decreases as the glucose concentration increases. By placing the time for U on the same scale as the standards, the glucose concentration in U can be estimated. If the time lies between two standard times, the concentration is estimated by linear interpolation between those two standards.

Understanding the Question

You have a time for U from (a)(iii) and a table of times for the standards from (a)(ii). You need to read across the table to find which standard time is closest to U's time and quote the corresponding concentration (or interpolate if U falls between two standards).

Approach

Locate the time for U in the results table. If it is closest to one particular standard, quote that standard's concentration. If it falls between two standards, estimate the concentration by linear interpolation between them.

Step-by-Step Reasoning

  • Representative standards: 20% = 32 s, 18% = 45 s, 16% = 60 s, 14% = 90 s, 12% = 150 s.
  • Representative time for U = 35 s, which lies between 20% (32 s) and 18% (45 s) and is much closer to 20%.
  • Linear interpolation: U is 35324532=3130.23\frac{35 - 32}{45 - 32} = \frac{3}{13} \approx 0.23 of the way from 20% to 18%, i.e. about 0.5% below 20%, giving ≈ 19.5%, which rounds to 19%.
  • The mark scheme accepts a reasonable estimate from the student's own data, so anything between about 18% and 20% would be credited here.

Key Takeaways

  • The closer the standards bracket the unknown, the more accurate the estimate - this is why (a)(v) suggests a narrower range of standards around U's estimate.
  • Linear interpolation between two adjacent standards is the standard way to estimate an intermediate value.

Common Mistakes

  • Picking the standard whose time is the same as U's, when U's time lies between two standards (interpolate instead).
  • Quoting a value outside the range of the standards (e.g. saying 25% when 20% is the highest standard).
  • Quoting a value without any reference to the recorded data (must come from the student's own table).

Things to Be Careful About

  • The estimate should be expressed to a sensible precision - usually to the nearest whole percent or to one decimal place, not to several significant figures that are not justified by the data.
Techniques used
locate the time for the unknown among the standard timesestimate an unknown value by interpolation between two standards
(v)

Describe how you would modify this procedure to give a more accurate estimate of U.

3M
DifficultyMedium
Worked solution

Answer

  1. Use a narrower range of concentrations centred around the estimated value of U (e.g. between 18% and 22%).
  2. Plot a graph of time against concentration for the standards and read off the concentration of U from the calibration curve.
  3. Repeat the measurements for all standard concentrations and for U, and calculate the means of the repeated times.

(Any three of the six mark-scheme points are accepted; alternative acceptable points include using at least five more concentrations in the narrower range, using a colorimeter to detect the end-point, and running the reactions one at a time / staggering the start times.)

Final answer

Use a narrower concentration range centred on the estimate of U; plot a calibration graph and read off U; repeat measurements and calculate means.

Detailed explanation

Background Concept

Improving the accuracy of an estimate usually means reducing random error (by replication and means), reducing systematic error (by more precise end-point detection), and improving the resolution of the calibration (by using a narrower range of standards centred on the unknown, and by reading off a graph rather than a single nearest-standard match).

Understanding the Question

You have estimated the glucose concentration in U using a coarse dilution series (20 to 12% in 2% steps) and a single read-off against the nearest standard. The examiner is asking what changes to the procedure would make this estimate more accurate.

Approach

The most effective set of improvements targets the two main weaknesses of the current procedure: the coarse concentration steps, and the fact that the time is taken only once. The first is fixed by using a narrower, denser set of standards and reading off a graph; the second is fixed by replication and means.

Step-by-Step Reasoning

The mark scheme offers six creditworthy improvements (any three earn full marks):

  1. Use a narrower range of concentrations centred on the estimate of U: a calibration curve is most accurate where the standards are densest, so the standards should cluster around U's estimated value rather than span a wide range.
  2. Use at least five more concentrations within this narrower range: a denser set of standards gives more points on the calibration curve and a more accurate read-off.
  3. Plot a graph of time against concentration for the standards and read off U: graphical interpolation is more accurate than a single nearest-standard match.
  4. Repeat measurements for all standards and for U, and calculate means: repetition reduces the effect of random error in the end-point judgement.
  5. Use a colorimeter (or record a video of the reaction with a visible timer, or use several independent observers): an instrumental or multi-observer end-point is more objective than a single human judgement.
  6. Run the reactions one at a time (or stagger the start times): avoids the difficulty of recording end-points for several simultaneously running reactions.

Key Takeaways

  • Accuracy is improved by reducing both random error (replication, better timing) and systematic error (calibration resolution, objective end-point detection).
  • A calibration graph plus a narrow standard range is the most accurate way to estimate an unknown from a reaction-time assay.

Common Mistakes

  • Vague answers such as 'be more careful' or 'do it again' - these are not creditworthy because they are not specific to the procedure.
  • Suggesting changes that are not feasible in a school lab (e.g. mass spectrometry).
  • Listing changes that would not actually improve accuracy (e.g. using a larger volume of P, which would simply change the time scale without improving the precision of the read-off).

Things to Be Careful About

  • The mark scheme caps this question at 3 marks, so the examiner will only credit the first three creditworthy points you list - make sure each is a distinct, specific improvement.
Techniques used
suggest modifications to an experimental procedure to improve accuracypropose refinements to a calibration method
(vi)

State two significant sources of error when carrying out step 7.

2M
DifficultyMedium-Easy
Worked solution

Answer

  1. Starting the reactions in all the test-tubes at the same time makes it difficult to record accurately the time at which each tube reaches the end-point.
  2. The end-point (the point at which the purple colour just disappears) is subjective and difficult to judge by eye.
Final answer

Starting all reactions simultaneously makes accurate timing of each end-point difficult; the end-point itself is subjective and hard to judge.

Detailed explanation

Background Concept

A 'significant source of error' is one that has a material effect on the accuracy or precision of the measurement - not a generic 'human error'. For Paper 3, the source must be tied to a specific step in the procedure and a specific way in which that step is unreliable.

Understanding the Question

Step 7 of the procedure is the recording of the end-point times. You are asked for two significant sources of error that occur during this step.

Approach

Think about exactly what could go wrong while the timer is running. The two clearest problems are (i) the practical difficulty of watching several tubes at once and reading the timer at the right moment, and (ii) the fact that the end-point is a gradual colour change rather than a sharp transition.

Step-by-Step Reasoning

  • Source 1: All five (or more) reactions are started at the same time, but each one takes a different length of time to clear. The experimenter has to watch several tubes simultaneously, decide which is the next to clear, and read the timer at the precise moment of clearing. This is very difficult to do accurately, and small delays in noticing or reading the timer will cause appreciable error in the recorded time.
  • Source 2: The end-point is defined as 'P is completely colourless', but the colour change is gradual. Different observers will judge the end-point at slightly different stages, and the same observer may judge it differently on different occasions. The end-point is therefore subjective.

Key Takeaways

  • A 'source of error' must be specific to the procedure, not a vague statement.
  • The two main categories of error here are practical (timing multiple simultaneous reactions) and observational (judging a gradual colour change).

Common Mistakes

  • Vague answers such as 'human error' or 'the experimenter might make a mistake' - these are not creditworthy.
  • Naming errors that are not actually part of step 7 (e.g. errors in pipetting or in making up the dilutions).
  • Naming a source without explaining why it affects the result.

Things to Be Careful About

  • The question is about step 7 specifically, not about the procedure as a whole. Errors earlier in the procedure (e.g. dilutions) are not what is being asked for here.
Techniques used
identify a procedural error from a written methodrecognise a subjective judgement as a source of error
(vii)

Describe how you would modify this procedure to reduce one source of error as stated in (a)(vi).

1M
DifficultyEasy
Worked solution

Answer

Time each concentration separately - start the reaction in a single test-tube and record the time to the end-point, then move on to the next concentration.

(Equally acceptable: use a colorimeter to detect the end-point; record the reaction on video together with the timer and review later; use several independent observers and take the mean of their readings.)

Final answer

Time each concentration separately (or use a colorimeter; or record a video; or use several independent observers).

Detailed explanation

Background Concept

Once a source of error has been identified, the next step is to suggest a specific, practical change to the procedure that would reduce it. The improvement must be directly linked to the source - not a generic 'be more careful'.

Understanding the Question

You have just listed two sources of error in step 7. The question asks for one modification to the procedure that would reduce one of those sources of error.

Approach

Choose one of the two errors and propose a concrete change. The most straightforward change is to deal with the simultaneous-reactions problem by timing each one separately. Alternatively, the subjective end-point can be removed by using a colorimeter, video, or several observers.

Step-by-Step Reasoning

  • If the chosen error is the difficulty of timing several simultaneous reactions: time each concentration separately. Set up one tube, start the reaction, record the time to the end-point, then move on to the next tube.
  • If the chosen error is the subjectivity of the end-point: use a colorimeter set to the wavelength of permanganate absorption; the colorimeter will register the moment the absorbance falls below a defined threshold. Alternatively, record the reactions on video with the timer visible and review the video frame-by-frame later, or have several observers each call the end-point and take the mean of their times.

Any one of these modifications is worth the mark.

Key Takeaways

  • An 'improvement' must be specific to the procedure, not a generic call for more care.
  • A modification should clearly reduce the named error, not just alter the experiment in some unrelated way.

Common Mistakes

  • Vague answers such as 'be more accurate' or 'take more readings' - these do not target the specific error.
  • Suggesting a change that would not actually reduce the named error (e.g. using a different concentration of P would change the time scale but not the difficulty of timing several reactions).
  • Suggesting a change that is not feasible in a school lab (e.g. spectrophotometer with a flow cell).

Things to Be Careful About

  • The mark scheme only credits one modification here, so there is no need to list several - but they should be clearly tied to one of the errors in (a)(vi).
Techniques used
link a modification directly to a named source of errorpropose a practical change to reduce error in a timing procedure
(b)

An investigation was carried out into the effect of drinking an energy drink on blood glucose concentration over a period of 3 hours.

The results are shown in Table 1.3.

Table 1.3

time / hoursglucose concentration / mmol dm3\text{mmol dm}^{-3}
0.05.2
0.57.5
1.09.1
2.08.4
3.07.9

Plot a graph of the data in Table 1.3 on the grid in Fig. 1.1.

Use a sharp pencil for drawing graphs.

4M
DifficultyMedium
Worked solution

Answer

The graph shows blood glucose concentration rising rapidly from 5.2 mmol dm3\text{mmol dm}^{-3} at 0 hours to a peak of 9.1 mmol dm3\text{mmol dm}^{-3} at 1.0 hour, then declining gradually to 7.9 mmol dm3\text{mmol dm}^{-3} at 3.0 hours.

Key plot features (to satisfy the four mark points):

  • x-axis labelled 'time / hours', y-axis labelled 'glucose concentration / mmol dm3\text{mmol dm}^{-3}'.
  • x-axis scale 0.5 hours = 2 cm (labels at 0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0); y-axis scale 2 mmol dm3\text{mmol dm}^{-3} = 2 cm (labels at 0, 2, 4, 6, 8, 10) - or, as the alternative, 1 mmol dm3\text{mmol dm}^{-3} = 2 cm starting at 5.0 (labels at 5.0, 6.0, 7.0, 8.0, 9.0).
  • All five points plotted as small crosses (×) or dots in circles: (0.0, 5.2), (0.5, 7.5), (1.0, 9.1), (2.0, 8.4), (3.0, 7.9).
  • Points joined with a thin line, either as straight lines between consecutive points or as a smooth curve passing through (or very close to) all five points.
Final answer

Line graph of blood glucose concentration (mmol dm⁻³) against time (hours); a smooth curve rising from (0.0, 5.2) to a peak at (1.0, 9.1) and then falling to (3.0, 7.9).

Detailed explanation

Background Concept

A line graph is the right way to display data where the independent variable (here, time after drinking the energy drink) is continuous. Paper 3 graphs must follow specific conventions:

  • each axis is labelled with the quantity and its unit, separated by a solidus (e.g. 'time / hours');
  • the scale on each axis should be chosen so that the points are spread across a reasonable portion of the grid;
  • points are plotted precisely with a sharp pencil, as a small cross (×) or a dot in a circle (⊙);
  • the points are joined either as a smooth curve or as straight lines between consecutive points, drawn with a thin line.

Understanding the Question

You are given a table of blood glucose concentrations at five time points after drinking an energy drink. You must plot these on the blank grid in Fig. 1.1. The mark scheme awards one mark each for the axis labels, the scales, the plotting, and the joining of the points.

Approach

  1. Choose which quantity goes on which axis. Time is the independent variable and goes on the x-axis; blood glucose concentration is the dependent variable and goes on the y-axis.
  2. Choose a scale for each axis that allows all five points to be plotted clearly and that uses a reasonable portion of the grid.
  3. Plot each (time, concentration) pair as a small cross or dot in a circle.
  4. Join the points with a thin line - either a smooth curve or straight lines between consecutive points.

Step-by-Step Reasoning

  • x-axis: the time values are 0.0, 0.5, 1.0, 2.0 and 3.0 hours, a range of 3.0 hours. The mark scheme accepts 0.5 hours = 2 cm. With this scale, the data span 3.0×2/0.5=123.0 \times 2 / 0.5 = 12 cm of the available 25 cm of grid. Labels every 2 cm give labels at 0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0 hours - one label per major grid square - which the mark scheme explicitly accepts.
  • y-axis: the concentrations are 5.2, 7.5, 9.1, 8.4 and 7.9 mmol dm⁻³, a range of about 4 mmol dm⁻³. The mark scheme offers two acceptable scales: (a) 2 mmol dm⁻³ = 2 cm, with labels at 0, 2, 4, 6, 8, 10 (the data then sit between the 5.2 and 9.1 levels, using about 4-5 cm of the grid); or (b) 1 mmol dm⁻³ = 2 cm starting at 5.0, with labels at 5.0, 6.0, 7.0, 8.0, 9.0 (the data then use the full 8 cm of the labelled region). The second option is the closer fit to the data.
  • Plot the five points using the chosen scales. Each point should be a small cross (×) or a dot inside a circle (⊙), drawn with a sharp pencil. The five coordinates are (0.0, 5.2), (0.5, 7.5), (1.0, 9.1), (2.0, 8.4) and (3.0, 7.9).
  • Join the points with a thin line. A smooth curve passing through (or very close to) all five points shows the rapid rise to a peak at 1.0 hour followed by a gradual decline. Straight lines between consecutive points are equally acceptable; the mark scheme allows either. The line must be thin (drawn with a sharp pencil), not a heavy or fuzzy line.

Key Takeaways

  • The independent variable goes on the x-axis and the dependent variable on the y-axis.
  • 'Quantity / unit' is the CIE standard for axis labels.
  • Scales should be chosen to spread the data across a reasonable portion of the grid and should be labelled at regular intervals (every 2 cm on a standard Paper 3 grid).
  • Points are plotted precisely with a sharp pencil as small crosses (×) or dots in circles (⊙).
  • Points are joined with a thin line as either a smooth curve or straight lines between consecutive points.

Common Mistakes

  • Putting the independent variable on the y-axis (the wrong way round).
  • Forgetting the unit in the axis label, or using a non-standard format (e.g. 'time (hours)' or 'time-hours' instead of 'time / hours').
  • Choosing a scale that crowds all the points into one corner of the grid (e.g. starting the y-axis at 0 and labelling every 1 cm - this would give a huge graph with most of the action compressed at the bottom).
  • Plotting points as large dots or as circles without a centre mark, which makes it hard to read the exact value.
  • Joining the points with a 'dot-to-dot' line that wiggles between every point, when the data would be better fitted with a smooth curve or with straight lines between points.

Things to Be Careful About

  • The mark scheme caps the scales: x must be 0.5 hours = 2 cm; y must be either 2 mmol dm⁻³ = 2 cm (starting at 0) or 1 mmol dm⁻³ = 2 cm (starting at 5.0). Other 'nicer-looking' scales (e.g. 0.2 hours = 2 cm, or 0.5 mmol dm⁻³ = 2 cm) are not credited.
  • 'Labelled at least every 2 cm' means a label every major grid square on the standard Paper 3 grid.
  • The line must be thin (a sharp pencil is required by the rubric) and must pass through (or very close to) all five points - a line that misses a point is a 'best-fit' line and would not be credited here, where the points are exact and a smooth curve is the appropriate representation.
Techniques used
plot a line graph with appropriate axes, scales and labelsselect appropriate scales that use a significant portion of the gridplot data points accurately with small crosses or dots in circlesjoin points with a smooth curve passing through all points

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  • Q2Use of the Light Microscope · Presentation of Data and Observations · Manipulation, Measurement and Observation · Analysis, Conclusions and Evaluation21M
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