5054/22

Physics 5054/22May/June 2012

Cambridge O-Level · Theory · worked solutions for every part, with the mark scheme

10
questions
75
marks
105
minutes

Topics Forces · Energy, Work and Power · Current, Voltage and Resistance · Mass, Weight and Density · Transfer of Thermal Energy · Thermal Properties of Matter · +9 more

Q1Mass, Weight and DensityForcesFree sample

Fig. 1.1 shows apparatus used to obtain the readings for a graph of force against extension for a spring.

The masses added to the pan produce a force that stretches the spring.

(a)
(i)

State what is meant by the mass of a body.

1M
DifficultyEasy
Worked solution

Answer

The amount of matter (or substance / material) in a body.

Final answer

amount of matter

Detailed explanation

Walkthrough

Mass is defined as the amount of matter or substance contained in an object. It is a scalar quantity measured in kilograms (kg\text{kg}) or grams (g\text{g}).

Key Takeaways

  • Mass measures the quantity of matter in an object and is also a property that resists change in motion (inertia).
  • Mass remains the same regardless of gravitational field strength, unlike weight.

Common Mistakes

  • Confusing mass with weight (the gravitational force acting on an object, W=mgW = mg).
  • Defining mass as 'how heavy an object is'.

Things to Be Careful About

  • Ensure the definition refers to 'matter', 'substance', or 'material'.
Techniques used
recall definition of mass
(ii)

Describe how the scale is used to find the extension of the spring.

1M
DifficultyMedium-Easy
Worked solution

Answer

Read the position of the pointer on the scale with no load (or the pan only), then read the new position on the scale after adding masses, and calculate the difference between the two readings.

Final answer

Subtract the initial scale reading (unstretched) from the new scale reading (stretched)

Detailed explanation

Walkthrough

Extension is the increase in the length of the spring when a load is applied:

extension=stretched lengthunstretched length\text{extension} = \text{stretched length} - \text{unstretched length}

To find this with a scale, the candidate must record the initial pointer reading on the scale before masses are added (or with the empty pan), record the new pointer reading after adding masses, and subtract the initial reading from the new reading.

Key Takeaways

  • Extension is an increase in length (a difference between two scale readings), not simply the total length of the spring.

Common Mistakes

  • Stating that the pointer reading itself is the extension, rather than finding the difference between two readings.

Things to Be Careful About

  • Make sure to explicitly mention subtracting or taking the difference between readings.
Techniques used
measure extension from initial and final scale readings
(b)

Fig. 1.2 shows the force-extension graphs for two different springs.

(i)

A student states that spring B is easier to stretch than spring A.

Use values from Fig. 1.2 to explain what the student means.

1M
DifficultyMedium-Easy
Worked solution

Answer

For a given force (e.g. 15 N15\text{ N}), spring B has a larger extension (4.0 cm4.0\text{ cm}) than spring A (3.0 cm3.0\text{ cm}).

(Alternatively: to produce an extension of 4.0 cm4.0\text{ cm}, spring B requires a smaller force of 15 N15\text{ N} whereas spring A requires 20 N20\text{ N}.)

Final answer

For the same force, spring B extends more than spring A (e.g. at 15 N, extension of B = 4.0 cm and extension of A = 3.0 cm)

Detailed explanation

Walkthrough

'Easier to stretch' means that a spring requires less force to produce the same extension, or that a given force produces a greater extension.

To use values from Fig. 1.2:

  1. Choose a fixed force on the y-axis, for example F=15 NF = 15\text{ N}:
    • Spring A extension =3.0 cm= 3.0\text{ cm}
    • Spring B extension =4.0 cm= 4.0\text{ cm}
    • Since spring B stretches further for the same force, it is easier to stretch.
  2. Alternatively, choose a fixed extension on the x-axis, for example e=4.0 cme = 4.0\text{ cm}:
    • Force on spring A =20 N= 20\text{ N}
    • Force on spring B =15 N= 15\text{ N}
    • Since spring B requires less force for the same extension, it is easier to stretch.

Key Takeaways

  • On a force-extension graph (FF vs ee), a line with a smaller gradient represents a spring with a smaller spring constant kk, meaning it is easier to stretch.

Common Mistakes

  • Giving a qualitative explanation without quoting numerical values from the graph.

Things to Be Careful About

  • Include units with the read-off values (extN ext{N} and extcm ext{cm}).
Techniques used
compare values on a force-extension graph
(ii)

When a force of 25 N is applied, spring B reaches its limit of proportionality but spring A does not. Explain how Fig. 1.2 shows this.

1M
DifficultyMedium-Easy
Worked solution

Answer

At 25 N25\text{ N}, the graph for spring A is a straight line through the origin (force is directly proportional to extension), whereas the graph for spring B is curved / no longer straight.

Final answer

Graph for spring A is still a straight line, but graph for spring B is curved

Detailed explanation

Walkthrough

Hooke's Law states that force is directly proportional to extension (F=keF = ke), which appears as a straight line passing through the origin on a force-extension graph.

The limit of proportionality is the point beyond which force is no longer proportional to extension, meaning the graph ceases to be a straight line and begins to curve.

  • At F=25 NF = 25\text{ N}, the line for spring A remains completely straight, showing it has not exceeded its limit of proportionality.
  • For spring B, the line starts curving around 20 N20\text{ N}, so at 25 N25\text{ N} it is clearly curved, showing it has passed its limit of proportionality.

Key Takeaways

  • A straight line through the origin on a force-extension graph indicates that Hooke's Law is obeyed.
  • Curvature in a force-extension graph indicates that the limit of proportionality has been passed.

Common Mistakes

  • Confusing the limit of proportionality with the elastic limit (though they often occur at similar points, proportionality is specifically shown by the line no longer being straight).

Things to Be Careful About

  • Refer clearly to both springs: A is straight / linear, and B is curved / non-linear.
Techniques used
interpret linearity and limit of proportionality on a graph
(iii)

The same force is applied to each spring.

Using Fig. 1.2, determine the force that produces an extension of spring B that is 1.0 cm greater than the extension of spring A.

force = ______

1M
DifficultyMedium-Easy
Worked solution

Working

We look for a horizontal line (same force FF) where the extension of spring B minus the extension of spring A equals 1.0 cm1.0\text{ cm}:

  • At F=15 NF = 15\text{ N}:
    extension of A=3.0 cm\text{extension of A} = 3.0\text{ cm}
    extension of B=4.0 cm\text{extension of B} = 4.0\text{ cm}
    Δe=4.0 cm3.0 cm=1.0 cm\Delta e = 4.0\text{ cm} - 3.0\text{ cm} = 1.0\text{ cm}

Answer

15 N15\text{ N}

Final answer

15 N

Detailed explanation

Walkthrough

The question specifies that the same force is applied to each spring. On the graph, 'the same force' corresponds to a horizontal line across at some value of FF on the vertical axis.

We need to find the force value where the horizontal distance between the two lines is exactly 1.0 cm1.0\text{ cm}:

  • At F=5 NF = 5\text{ N}: eA=1.0 cme_A = 1.0\text{ cm}, eB=1.3 cme_B = 1.3\text{ cm} (difference =0.3 cm= 0.3\text{ cm})
  • At F=10 NF = 10\text{ N}: eA=2.0 cme_A = 2.0\text{ cm}, eB=2.7 cme_B = 2.7\text{ cm} (difference =0.7 cm= 0.7\text{ cm})
  • At F=15 NF = 15\text{ N}: eA=3.0 cme_A = 3.0\text{ cm}, eB=4.0 cme_B = 4.0\text{ cm} (difference =1.0 cm= 1.0\text{ cm})

Thus, the force is 15 N15\text{ N}.

Key Takeaways

  • Comparing two curves at the same y-value means checking the horizontal distance between them at that value.

Common Mistakes

  • Reading vertical separation (difference in force at the same extension) instead of horizontal separation (difference in extension at the same force).

Things to Be Careful About

  • Ensure the unit (extN ext{N}) is stated with the answer.
Techniques used
read coordinates from a graph to find a specified difference

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