5054/31

Physics 5054/31October/November 2011

Cambridge O-Level · Practical Test · worked solutions for every part, with the mark scheme

4
questions
30
marks
120
minutes

Topics Experimental Contexts · Use of Techniques, Apparatus and Materials · Observations and Measurements · Analysis, Conclusions and Evaluation

Q15MExperimental ContextsUse of Techniques, Apparatus and MaterialsObservations and MeasurementsAnalysis, Conclusions and EvaluationFree sample

In this experiment, you will investigate the equilibrium of a suspended mass.

You have been provided with

  • a mass, labelled M, suspended from a stand and clamp by a length of string,
  • a second length of string attached to the first length of string at one end and with a loop at the other end,
  • a pulley supported above the bench,
  • a 50 g50\text{ g} mass with a hook,
  • a metre rule,
  • a set square.
(a)

Set up the apparatus as shown in Fig. 1.1.

Pass the second length of string over the pulley and suspend the 50 g50\text{ g} mass from the loop. Adjust the position and height of the pulley so that string BC is horizontal.

DifficultyEasy
Worked solution

Answer

Apparatus set up as shown in Fig. 1.1, with string BC adjusted to be horizontal.

Final answer

See Fig. 1.1

Detailed explanation

Walkthrough

The candidate is given a list of apparatus and asked to assemble it as shown in the diagram. The key feature to achieve is that the string segment BC, which runs over the pulley to the 50 g mass, must be horizontal. This is done by adjusting the position and height of the pulley.

Key Takeaways

Candidates must be able to follow instructions to assemble a practical apparatus and make fine adjustments to achieve a specific geometric condition (a horizontal string).

Common Mistakes

Failing to adjust the pulley height so that BC is truly horizontal, which will introduce errors in the angle θ\theta and invalidate the equilibrium assumption used in later calculations.

Things to Be Careful About

This is a Paper 3 practical question. The candidate performs the setup themselves. Ensure the string is taut and the mass M hangs freely without touching the stand or bench.

Techniques used
set up a string and pulley equilibrium apparatus
(b)

Explain how you made sure that BC was horizontal. You may add to Fig. 1.1 if you wish.

1M
DifficultyEasy
Worked solution

Answer

Measured the height of the string BC above the bench at two different points using a metre rule and confirmed they were equal. Alternatively, placed a set square against the vertical stand and checked that the angle MBC was 9090^\circ.

Final answer

Measured the height of the string above the bench at two places and confirmed they were equal, or used a set square to check the angle MBC was 9090^\circ.

Detailed explanation

Walkthrough

To ensure BC is horizontal, the candidate must use one of the provided tools (metre rule or set square) to verify the alignment. The most direct method is to measure the vertical distance from the bench to the string BC at two separate points along its length; if the distances are identical, the string is horizontal. Another valid method is to use the set square to check that the angle between the vertical stand (or a vertical line) and the string BC is exactly 9090^\circ.

Key Takeaways

Practical skills involve using simple apparatus (rulers, set squares) to verify geometric conditions required for the experiment to be valid.

Common Mistakes

Saying 'looked along the string' without using an instrument, or suggesting 'aligned with the bench' without explaining how that measurement is made.

Things to Be Careful About

The mark scheme accepts either measuring heights at two points or using a set square. Both must be described as a method of verification, not just 'checking' visually.

Techniques used
use a metre rule to check horizontal alignmentuse a set square to verify a right angle
(c)

Measure and record the vertical heights h1h_1 and h2h_2 shown in Fig. 1.1. Also measure and record the length ll of the string between the two points A and B.

h1h_1 = ______
h2h_2 = ______
ll = ______

2M
DifficultyMedium-Easy
Worked solution

Answer

h1=45.0 cmh_1 = 45.0 \text{ cm}
h2=22.0 cmh_2 = 22.0 \text{ cm}
l=25.0 cml = 25.0 \text{ cm}

(Note: These are representative values. Candidate readings must have ll between 24.0 cm24.0 \text{ cm} and 26.0 cm26.0 \text{ cm}, l>h1h2l > h_1 - h_2, and all lengths recorded to the nearest mm or better with units.)

Final answer

Candidate-dependent readings (e.g. h1=45.0 cmh_1 = 45.0 \text{ cm}, h2=22.0 cmh_2 = 22.0 \text{ cm}, l=25.0 cml = 25.0 \text{ cm}), recorded to the nearest mm with units.

Detailed explanation

Walkthrough

The candidate uses a metre rule to measure three quantities from Fig. 1.1:

  • h1h_1: the vertical height from the bench to point A (the split cork).
  • h2h_2: the vertical height from the bench to point B (the junction of the strings).
  • ll: the length of the string segment AB.

For the subsequent calculation of θ\theta to fall in the acceptable range (5050^\circ to 7070^\circ), the difference (h1h2)(h_1 - h_2) must be roughly 0.77l0.77l to 0.94l0.94l. Using l=25.0 cml = 25.0 \text{ cm}, a suitable difference is 23.0 cm23.0 \text{ cm}, giving h1=45.0 cmh_1 = 45.0 \text{ cm} and h2=22.0 cmh_2 = 22.0 \text{ cm}.

Key Takeaways

Practical measurements must be taken to the precision of the instrument (nearest mm for a metre rule) and always include units. The values must also be physically consistent with the apparatus geometry (ll must be greater than the vertical difference h1h2h_1 - h_2).

Common Mistakes

Forgetting to include units, recording to the wrong precision (e.g. nearest cm instead of mm), or providing values where l<h1h2l < h_1 - h_2 (which is geometrically impossible for a right-angled triangle with hypotenuse ll).

Things to Be Careful About

The metre rule is read to the nearest mm, so a reading like 25.0 cm25.0 \text{ cm} (or 250 mm250 \text{ mm}) is correct, but 25 cm25 \text{ cm} without the trailing zero may be penalised for precision. Ensure l>h1h2l > h_1 - h_2 is explicitly checked.

Techniques used
measure vertical heights and string length with a metre rulerecord readings to the nearest mm with units
(d)

Calculate the angle θ\theta between the string AB and the horizontal, using the relationship

sinθ=h1h2l\sin\theta = \frac{h_1 - h_2}{l}

θ\theta = ______

2M
DifficultyMedium-Easy
Worked solution

Working

sinθ=h1h2l=45.022.025.0=23.025.0=0.92\sin\theta = \frac{h_1 - h_2}{l} = \frac{45.0 - 22.0}{25.0} = \frac{23.0}{25.0} = 0.92 θ=sin1(0.92)=66.9\theta = \sin^{-1}(0.92) = 66.9^\circ

Answer

66.966.9^\circ

(Note: Candidate-dependent calculation. Value of θ\theta should be in the range 5050^\circ to 7070^\circ with units.)

Final answer

Candidate-dependent calculation (e.g. 66.966.9^\circ), value in range 5050^\circ to 7070^\circ with units.

Detailed explanation

Walkthrough

The candidate substitutes their recorded values from part (c) into the provided equation:

sinθ=h1h2l\sin\theta = \frac{h_1 - h_2}{l}

Using the representative values: h1h2=45.022.0=23.0 cmh_1 - h_2 = 45.0 - 22.0 = 23.0 \text{ cm}, and l=25.0 cml = 25.0 \text{ cm}.

sinθ=23.025.0=0.92\sin\theta = \frac{23.0}{25.0} = 0.92

Then, use the inverse sine function (sin1\sin^{-1} or arcsin\arcsin) on a calculator to find θ\theta:

θ=sin1(0.92)66.9\theta = \sin^{-1}(0.92) \approx 66.9^\circ

The mark scheme requires the candidate to show the calculation of sinθ\sin\theta and then the final angle θ\theta in degrees, with the unit.

Key Takeaways

Candidates must correctly substitute measured values into a trigonometric relationship and use their calculator's inverse trig functions, remembering to include the unit (^\circ) in the final answer.

Common Mistakes

Forgetting to use the inverse sine function (e.g. answering 0.920.92^\circ instead of 66.966.9^\circ), forgetting the degree symbol in the final answer, or carrying forward an error from part (c) without showing the working for sinθ\sin\theta.

Things to Be Careful About

Ensure the calculator is in degree mode, not radian mode. The mark scheme awards a method mark (C1) for the correct calculation of sinθ\sin\theta and an answer mark (A1) for the final value of θ\theta in the range 5050^\circ to 7070^\circ with the unit. Error carried forward (ecf) from part (c) is allowed if the method is correct.

Techniques used
apply the sine relationship to find an angleuse an inverse sine function on a calculator

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