4037/12

Additional Mathematics 4037/12May/June 2013

Cambridge O-Level · Calculator · worked solutions for every part, with the mark scheme

12
questions
80
marks
120
minutes

Topics Calculus · Trigonometry · Quadratic functions · Straight-line graphs · [Legacy] Set language and notation · Permutations and combinations · +4 more

Q1[Legacy] Set language and notationFree sample

The Venn diagram shows the universal set E\mathscr{E}, the set AA and the set BB. Given that n(B)=5\mathrm{n}(B) = 5, n(A)=10\mathrm{n}(A') = 10 and n(E)=26\mathrm{n}(\mathscr{E}) = 26, find

(i)

n(AB)\mathrm{n}(A \cap B),

1M
DifficultyEasy
Worked solution

Approach

From the Venn diagram, BB lies entirely inside AA, so BAB \subset A. Therefore every element of BB is also in AA, and AB=BA \cap B = B.

Working

n(AB)=n(B)=5\mathrm{n}(A \cap B) = \mathrm{n}(B) = 5

Answer

n(AB)=5\mathrm{n}(A \cap B) = 5
Final answer

5

Detailed explanation

Walkthrough

The diagram shows the circle for BB drawn completely inside the oval for AA, which means BB is a subset of AA. The intersection of a set with its own subset is just the subset itself, so AB=BA \cap B = B. Since n(B)=5\mathrm{n}(B) = 5, we get n(AB)=5\mathrm{n}(A \cap B) = 5.

Key Takeaways

  • If BAB \subset A, then AB=BA \cap B = B and AB=AA \cup B = A.
  • Reading the containment relationship from the picture is the whole task here.

Common Mistakes

  • Treating AA and BB as overlapping sets and trying to compute the intersection from totals.
  • Confusing ABA \cap B with ABA \cup B.

Things to Be Careful About

  • The answer is exact (a B1 mark, cao): it must be 55, not any other value.
  • Note the diagram shows BB strictly inside AA — there is no region of BB outside AA.
Techniques used
read the subset relationship from the Venn diagramidentify the intersection of a set with its subset
(ii)

n(A)\mathrm{n}(A),

1M
DifficultyEasy
Worked solution

Approach

The complement AA' contains all elements of the universal set E\mathscr{E} that are not in AA, so n(A)=n(E)n(A)\mathrm{n}(A) = \mathrm{n}(\mathscr{E}) - \mathrm{n}(A').

Working

n(A)=n(E)n(A)=2610=16\mathrm{n}(A) = \mathrm{n}(\mathscr{E}) - \mathrm{n}(A') = 26 - 10 = 16

Answer

n(A)=16\mathrm{n}(A) = 16
Final answer

16

Detailed explanation

Walkthrough

The universal set has 2626 elements and 1010 of them lie outside AA (in AA'). The elements of AA are therefore the remaining 2610=1626 - 10 = 16.

Key Takeaways

  • n(A)+n(A)=n(E)\mathrm{n}(A) + \mathrm{n}(A') = \mathrm{n}(\mathscr{E}) for any set AA.

Common Mistakes

  • Subtracting the wrong way round, or using n(B)=5\mathrm{n}(B) = 5 unnecessarily.

Things to Be Careful About

  • The value n(B)=5\mathrm{n}(B) = 5 is not needed in this part — do not mix it in.
Techniques used
use the complement rule n(A) = n(E) - n(A')
(iii)

n(BA)\mathrm{n}(B' \cap A).

1M
DifficultyEasy
Worked solution

Approach

The region BAB' \cap A is the part of AA that lies outside BB — the crescent between the oval AA and the inner circle BB. Its count is n(A)n(B)\mathrm{n}(A) - \mathrm{n}(B).

Working

n(BA)=n(A)n(B)=165=11\mathrm{n}(B' \cap A) = \mathrm{n}(A) - \mathrm{n}(B) = 16 - 5 = 11

Answer

n(BA)=11\mathrm{n}(B' \cap A) = 11
Final answer

11

Detailed explanation

Walkthrough

Since BAB \subset A, the set AA splits into two disjoint pieces: the part inside BB (with 55 elements) and the part of AA outside BB, which is exactly BAB' \cap A. So n(BA)=165=11\mathrm{n}(B' \cap A) = 16 - 5 = 11, using n(A)=16\mathrm{n}(A) = 16 from part (ii).

Key Takeaways

  • BAB' \cap A means 'in AA but not in BB'; when BAB \subset A its count is n(A)n(B)\mathrm{n}(A) - \mathrm{n}(B).
  • Parts of a multi-part Venn question build on each other — the value n(A)=16\mathrm{n}(A) = 16 is carried forward.

Common Mistakes

  • Using n(E)=26\mathrm{n}(\mathscr{E}) = 26 instead of n(A)=16\mathrm{n}(A) = 16.
  • Misreading BAB' \cap A as the whole of AA'.

Things to Be Careful About

  • The answer must be exactly 1111 (B1, cao). Keep the intermediate value n(A)=16\mathrm{n}(A) = 16 exact — no rounding issues arise here.
Techniques used
identify the region B' intersect A on the Venn diagramsubtract the subset count from the containing set count

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